To calculate the force applied on an area based on the pressure, we use the formula:

$F = P \times A$

Where:

• $F$ is the force (in Newtons, N),
• $P$ is the pressure (in $\text{N/m}^2$ or Pascals),
• $A$ is the area (in $\text{m}^2$).

Given:

• Pressure $P = 100 \, \text{kN/m}^2 = 100,000 \, \text{N/m}^2$,
• Area $A = 0.07 \, \text{m}^2$.

Now, substitute the values:

$F = 100,000 \, \text{N/m}^2 \times 0.07 \, \text{m}^2 = 7,000 \, \text{N}$

So, the force applied is $7,000 \, \text{N}$.

Would you like further details or have any questions?

Here are 5 related questions for further exploration:

1. What happens to the force if the area doubles but the pressure stays constant?
2. How would the force change if the pressure increases to 150 kN/m²?
3. Can you calculate the pressure if the force is known and the area is 0.05 m²?
4. How is this concept applied in hydraulic systems or piston designs?
5. What unit conversions are needed if the pressure is given in bar instead of kN/m²?

Tip: Always make sure units are consistent when calculating force, pressure, and area to avoid mistakes!