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The problem asks you to calculate the force on a grain of rice using the equation \( F = ma \), where:

- \( m = 2.9 \times 10^{-5} \, \text{kg} \) is the mass of the grain of rice,
- \( a = 9.8 \, \text{m/s}^2 \) is the acceleration due to gravity.

Let's calculate the force.

\[
F = m \times a = (2.9 \times 10^{-5}) \times 9.8
\]

I will calculate the result.The force acting on the grain of rice is \( 0.0002842 \, \text{N} \), which can be written in scientific notation as \( 2.842 \times 10^{-4} \, \text{N} \).

The correct answer from the options provided is **2.842 × 10⁻⁴**.

Would you like further details, or do you have any other questions?

Here are some related questions for further exploration:

1. How do you convert a number into scientific notation?
2. What is the significance of the gravitational constant in this calculation?
3. How does the mass of an object affect the force due to gravity?
4. How would the force change if the object were on the Moon instead of Earth?
5. What are some examples of using \( F = ma \) in everyday situations?

**Tip:** When solving problems with scientific notation, always ensure the units are consistent before multiplying or dividing values.

The equation F = ma states that the force F on an object is equal to the mass m of the object times the acceleration a of the object. The force is measured in a unit called 'newtons'. A single grain of long grain rice has a mass of 2.9 × 10^-5 kg. If this grain of rice is dropped, the acceleration it will have due to gravity is 9.8 m/s². Use the above equation to calculate the amount of force on the grain of rice. Choose the answer that represents this value in scientific notation.

Learn how to calculate the force acting on a grain of rice with a mass of 2.9 × 10^-5 kg using Newton's Second Law (F = ma) and the acceleration due to gravity (9.8 m/s²). This problem demonstrates how to apply scientific notation and the formula F = ma to solve real-world physics problems.

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