Math Problem Statement

Sound travels about 750 miles per hour. If you stand in a canyon and sound a horn, you will hear an echo.

Round your answers to the nearest tenth as needed.

a) Suppose it takes about 4 seconds to hear the echo. How far away is the canyon wall, in feet?

The canyon wall is  feet away.

b) Suppose you stand 1,925 feet from the canyon wall and sound the horn. How long will it take to hear the echo?

It will take  seconds to hear the echo.

Solution

Part a: Finding the distance to the canyon wall

Given that sound travels at approximately 750 miles per hour, and it takes 4 seconds to hear the echo, the question asks for the distance to the canyon wall in feet.

Step 1: Convert the speed of sound to feet per second.

First, we need to convert the speed of sound from miles per hour to feet per second:

1 mile=5280 feet1 \text{ mile} = 5280 \text{ feet} 750 miles per hour=750×5280=3,960,000 feet per hour750 \text{ miles per hour} = 750 \times 5280 = 3,960,000 \text{ feet per hour} Since there are 3600 seconds in an hour, the speed of sound in feet per second is:

3,960,0003600=1,100 feet per second\frac{3,960,000}{3600} = 1,100 \text{ feet per second}

Step 2: Calculate the total distance traveled by sound.

In 4 seconds, the total distance the sound travels (there and back) is:

Distance traveled=1,100 feet/second×4 seconds=4,400 feet\text{Distance traveled} = 1,100 \text{ feet/second} \times 4 \text{ seconds} = 4,400 \text{ feet}

Step 3: Calculate the distance to the canyon wall.

Since the sound travels to the canyon wall and back (i.e., the total distance is twice the distance to the wall), the distance to the canyon wall is:

Distance to the canyon wall=4,4002=2,200 feet\text{Distance to the canyon wall} = \frac{4,400}{2} = 2,200 \text{ feet}

So, the canyon wall is 2,200 feet away.

Part b: Finding the time for the echo

Now, you are 1,925 feet away from the canyon wall, and we need to determine how long it takes to hear the echo.

Step 1: Calculate the total distance traveled by sound.

The sound travels to the wall and back, so the total distance the sound travels is:

Total distance=2×1,925=3,850 feet\text{Total distance} = 2 \times 1,925 = 3,850 \text{ feet}

Step 2: Calculate the time taken.

Since sound travels at 1,100 feet per second, the time it takes to travel 3,850 feet is:

Time=3,850 feet1,100 feet/second3.5 seconds\text{Time} = \frac{3,850 \text{ feet}}{1,100 \text{ feet/second}} \approx 3.5 \text{ seconds}

So, it will take approximately 3.5 seconds to hear the echo.

Final Answers:

  • a) The canyon wall is 2,200 feet away.
  • b) It will take about 3.5 seconds to hear the echo.

Do you need further details or have any questions?


Here are some related questions to explore:

  1. How does temperature affect the speed of sound?
  2. What if the sound took 6 seconds to return—how far would the canyon wall be?
  3. How would the echo time change if the canyon wall was 3,000 feet away?
  4. What is the relationship between distance and time for sound waves?
  5. How fast does sound travel in water compared to air?

Tip: The speed of sound varies with altitude and air temperature.

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Math Problem Analysis

Mathematical Concepts

Distance, Speed, and Time Relationship
Unit Conversion
Algebra

Formulas

Speed = Distance / Time
1 mile = 5280 feet
Total distance traveled by sound = 2 * Distance to the canyon wall

Theorems

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Suitable Grade Level

Grades 7-10