https://file.aiquickdraw.com/mathbot/file/1726108638353i8re88e2.jpg

Let's break down and solve each part of the problem in the image:

### (a) Finding the original price before the discount:
Jayden paid **$40.50** for the shoes after enjoying a **25% discount**.

Let the original price be $ x $. Since he received a 25% discount, he only paid 75% of the original price:
\[
0.75 \times x = 40.50
\]

To find $ x $ (the original price), divide both sides by 0.75:
\[
x = \frac{40.50}{0.75} = 54.00
\]
So, the original price before the discount was **$54.00**.

### (b) Calculating Jayden's total allowance:
The price Jayden paid, **$40.50**, is **15%** of his total monthly allowance. Let his total allowance be $ y $. The equation is:
\[
0.15 \times y = 40.50
\]

To find $ y $, divide both sides by 0.15:
\[
y = \frac{40.50}{0.15} = 270.00
\]
Thus, Jayden's total allowance for the month is **$270.00**.

---

Would you like further details or have any questions about the solution? 

Here are 5 related questions you can explore:
1. What if Jayden had received a 30% discount instead of 25%? What would the original price be?
2. If Jayden's allowance was increased by 10%, what would his new total allowance be?
3. How much would Jayden have paid if he had only a 10% discount on the shoes?
4. If Jayden spent 40% of his allowance on other items, how much does he have left?
5. If Jayden wants to save 20% of his allowance, how much can he save each month?

**Tip**: When working with percentages, always relate them to the base value (e.g., the original price or total allowance).

Jayden enjoyed a 25% discount when he bought a pair of shoes. If he paid $40.50 for the shoes, what was the original price before the discount?
The price Jayden paid for the pair of shoes is 15% of his total allowance for the month. Calculate his total allowance.

Learn how to calculate the original price of shoes after a 25% discount and determine Jayden's total monthly allowance, given that he paid 15% of it for the shoes. This step-by-step guide covers percentage calculations and basic algebra for middle school students.

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