Math Problem Statement

The limit of the difference quotient expression to find the derivative of a function as \( \Delta x \to 0 \): \( \lim_{\Delta x \to 0} \frac{(5 + \Delta x)^2 - 3(2 + \Delta x) + 9 - (25 - 6 + 9)}{\Delta x} \)

Solution

The given image depicts the difference quotient expression used in calculus, which is a core step in deriving the derivative of a function using limits. Let's break it down:

limΔx0(5+Δx)23(2+Δx)+9(523(2)+9)Δx\lim_{\Delta x \to 0} \frac{(5 + \Delta x)^2 - 3(2 + \Delta x) + 9 - (5^2 - 3(2) + 9)}{\Delta x}

To clarify, this limit formula is designed to compute the derivative of a given function f(x)f(x) at a specific point by using the difference quotient.

Here's a step-by-step breakdown of how to simplify and solve this expression:

Step 1: Expand the terms inside the numerator

  1. Expand (5+Δx)2(5 + \Delta x)^2 using the binomial formula: (5+Δx)2=25+10Δx+(Δx)2(5 + \Delta x)^2 = 25 + 10\Delta x + (\Delta x)^2

  2. Distribute 3-3 over (2+Δx)(2 + \Delta x): 3(2+Δx)=63Δx-3(2 + \Delta x) = -6 - 3\Delta x

Step 2: Substitute expanded forms back into the difference quotient

(25+10Δx+(Δx)2)(6+3Δx)+9(256+9)Δx\frac{(25 + 10\Delta x + (\Delta x)^2) - (6 + 3\Delta x) + 9 - (25 - 6 + 9)}{\Delta x}

Step 3: Simplify the constant terms

The expression 256+925 - 6 + 9 results in: 256+9=2825 - 6 + 9 = 28

Thus, the numerator becomes: (25+10Δx+(Δx)2)(6+3Δx)+928(25 + 10\Delta x + (\Delta x)^2) - (6 + 3\Delta x) + 9 - 28

Step 4: Combine like terms

Simplifying the constants and combining terms involving Δx\Delta x: (256+928)+(10Δx3Δx)+(Δx)2=0+7Δx+(Δx)2(25 - 6 + 9 - 28) + (10\Delta x - 3\Delta x) + (\Delta x)^2 = 0 + 7\Delta x + (\Delta x)^2

So, the expression becomes: 7Δx+(Δx)2Δx\frac{7\Delta x + (\Delta x)^2}{\Delta x}

Step 5: Simplify the expression by canceling Δx\Delta x

Factor Δx\Delta x from the numerator: Δx(7+Δx)Δx\frac{\Delta x(7 + \Delta x)}{\Delta x}

Cancel out the Δx\Delta x: 7+Δx7 + \Delta x

Step 6: Take the limit as Δx0\Delta x \to 0

As Δx0\Delta x \to 0, the expression becomes: 77

Thus, the derivative (or the value of the limit) is 77.

Final Answer:

limΔx0(5+Δx)23(2+Δx)+9(256+9)Δx=7\lim_{\Delta x \to 0} \frac{(5 + \Delta x)^2 - 3(2 + \Delta x) + 9 - (25 - 6 + 9)}{\Delta x} = 7

Would you like more details on any specific steps or have any other questions?

Here are some related questions for further practice:

  1. How do you find the derivative of a quadratic function in general?
  2. Can the difference quotient method be applied to any function?
  3. How would you apply this method to the function f(x)=3x25x+2f(x) = 3x^2 - 5x + 2?
  4. What does the derivative represent geometrically?
  5. How do you interpret the limit in terms of instantaneous rate of change?

Tip: Always simplify and group like terms before applying the limit to make the calculations smoother.

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Math Problem Analysis

Mathematical Concepts

Calculus
Limits
Difference Quotient
Derivatives

Formulas

\( f'(x) = \lim_{\Delta x \to 0} \frac{f(x + \Delta x) - f(x)}{\Delta x} \)

Theorems

Derivative Definition

Suitable Grade Level

Grades 11-12