80.5 g of C4H8 react with excess O2 by the equation below. Determine the mass of of CO2 that can be produced.

C4H8(g) + 6O2(g) -> 4CO2(g) + 4H2O(l)

To determine the mass of CO₂ produced from the combustion of 80.5 g of C₄H₈, we can follow these steps:

1. **Calculate the molar mass of C₄H₈**:
   \[
   \text{Molar mass of C₄H₈} = (4 \times 12.01 \, \text{g/mol}) + (8 \times 1.008 \, \text{g/mol}) = 48.1 \, \text{g/mol} + 8.064 \, \text{g/mol} = 56.164 \, \text{g/mol}
   \]

2. **Calculate the moles of C₄H₈**:
   \[
   \text{Moles of C₄H₈} = \frac{80.5 \, \text{g}}{56.164 \, \text{g/mol}} \approx 1.43 \, \text{mol}
   \]

3. **Use the balanced equation to find moles of CO₂ produced**:
   According to the reaction:
   \[
   \text{C₄H₈} + 6\text{O₂} \rightarrow 4\text{CO₂} + 4\text{H₂O}
   \]
   1 mole of C₄H₈ produces 4 moles of CO₂. Therefore:
   \[
   \text{Moles of CO₂} = 1.43 \, \text{mol C₄H₈} \times \frac{4 \, \text{mol CO₂}}{1 \, \text{mol C₄H₈}} \approx 5.72 \, \text{mol CO₂}
   \]

4. **Calculate the mass of CO₂**:
   The molar mass of CO₂ is:
   \[
   \text{Molar mass of CO₂} = (12.01 \, \text{g/mol}) + (2 \times 16.00 \, \text{g/mol}) = 12.01 \, \text{g/mol} + 32.00 \, \text{g/mol} = 44.01 \, \text{g/mol}
   \]
   Therefore, the mass of CO₂ produced is:
   \[
   \text{Mass of CO₂} = \text{Moles of CO₂} \times \text{Molar mass of CO₂} = 5.72 \, \text{mol} \times 44.01 \, \text{g/mol} \approx 251.09 \, \text{g}
   \]

**Conclusion**: The mass of CO₂ produced is approximately **251.09 g**.

Would you like further details or explanations on any specific step? Here are some related questions you might find interesting:

1. What would happen if there was insufficient O₂ for the reaction?
2. How could you determine the amount of H₂O produced in this reaction?
3. What are the environmental impacts of CO₂ emissions from combustion?
4. How does the stoichiometry of this reaction compare to other hydrocarbon combustion reactions?
5. What methods can be used to capture CO₂ emissions? 

**Tip**: Always check the stoichiometry of a reaction to ensure you're using the correct mole ratios when calculating product masses.

80.5 g of C4H8 react with excess O2 by the equation below. Determine the mass of CO2 that can be produced.

Discover how to calculate the mass of CO2 produced from the combustion of 80.5 g of C4H8 with excess O2. This detailed solution covers molar mass calculations, stoichiometry, and key chemical concepts. Ideal for high school chemistry students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation