Math Problem Statement

Data was collected for 222 randomly selected 10-minute intervals. For each ten-minute interval, the number of people entering the atrium of a large mall were recorded. The data is summarized in the table below: Number of Guests | Frequency 200–209 | 28 210–219 | 68 220–229 | 30 230–239 | 46 240–249 | 50 What is the class width?

Solution

To determine the class width, we subtract the lower boundary of a class from the lower boundary of the next class.

For example: The first class is 200–209, and the second class is 210–219. The class width is calculated as: 210−200=10210 - 200 = 10

Thus, the class width is 10.

Would you like more details or have any questions?

Here are five related questions for further exploration:

  1. How do you determine the class midpoint for each interval?
  2. What is the total frequency in this data set?
  3. How would you calculate the relative frequency for each class?
  4. Can you identify the class boundaries for the intervals?
  5. How do you create a histogram using this data?

Tip: Always double-check the range between intervals to confirm the class width accurately.

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Math Problem Analysis

Mathematical Concepts

Statistics
Class Width

Formulas

Class Width = Lower Boundary of Next Class - Lower Boundary of Current Class

Theorems

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Suitable Grade Level

Grades 7-9

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