To solve these questions, we need to calculate the average speed for both parts of the trip.

Part A) Average speed during the first leg

The formula for average speed is:

$\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}$

For the first leg of the trip:

• Distance $d_1 = 42.1 \, \text{mi}$
• Time $t_1 = 1.18 \, \text{h}$

So, the average speed during the first leg is:

$\text{Average Speed}_1 = \frac{42.1 \, \text{mi}}{1.18 \, \text{h}} = 35.68 \, \text{mph}$

Part B) Average speed for the entire trip

For the entire trip:

• Distance $d_1 + d_2 = 42.1 \, \text{mi} + 130.7 \, \text{mi} = 172.8 \, \text{mi}$
• Time $t_1 + t_2 = 1.18 \, \text{h} + 2.07 \, \text{h} = 3.25 \, \text{h}$

The average speed over the entire trip is:

$\text{Average Speed}_{\text{total}} = \frac{172.8 \, \text{mi}}{3.25 \, \text{h}} = 53.17 \, \text{mph}$

Part C) Average speed in meters per second

To convert miles per hour (mph) to meters per second (m/s), we use the conversion factor:

$1 \, \text{mph} = 0.44704 \, \text{m/s}$

So, the average speed for the whole trip in meters per second is:

$\text{Average Speed}_{\text{total}} = 53.17 \, \text{mph} \times 0.44704 \, \text{m/s} = 23.77 \, \text{m/s}$

Summary of results:

• Part A: Average speed during the first leg = $35.68 \, \text{mph}$
• Part B: Average speed for the entire trip = $53.17 \, \text{mph}$
• Part C: Average speed for the whole trip in meters per second = $23.77 \, \text{m/s}$

Would you like more details on any part of the solution?

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Related Questions:

1. How would the average speed change if the time for the second leg was reduced?
2. What would the average speed be if the first leg was shorter by 10 miles?
3. How do you convert from kilometers per hour to meters per second?
4. What would happen to the average speed if there were a third leg added to the trip?
5. How does constant speed differ from average speed?

Tip: When converting units, always double-check the conversion factors to ensure accuracy!