Math Problem Statement
Gold, which has a density of 19.32g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold, with a mass of 27.63g, is pressed into a leaf of 1.00 μm thickness, what is the area of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.5 μm, what is the length of the fiber?
Solution
To solve these problems, we need to use the relationship between mass, density, and volume, as well as the geometric formulas for the volume of a thin sheet (a rectangular prism) and a cylindrical fiber.
(a) Area of the Leaf
Given:
- Density of gold:
- Mass of gold:
- Thickness of the leaf:
Step 1: Calculate the volume of gold.
We know the relationship:
Step 2: Calculate the area of the leaf.
Since the leaf is a rectangular prism, the volume can also be expressed as: Substituting the values:
(b) Length of the Cylindrical Fiber
Given:
- Radius of the fiber:
Step 1: Calculate the cross-sectional area of the cylinder.
The cross-sectional area of a cylinder is given by: Substituting the radius:
Step 2: Calculate the length of the fiber.
The volume of the cylindrical fiber can also be expressed as: Substituting the values:
Final Answers:
- (a) The area of the leaf is 1.43 10 cm.
- (b) The length of the fiber is 72.84 km.
Would you like more details or have any questions?
Here are 5 related questions:
- How does the density of a material affect its volume for a given mass?
- What are some practical applications of gold’s ductility in industry?
- How would changing the thickness of the leaf affect its area?
- What would happen to the length of the fiber if the radius were halved?
- Can you calculate the volume of gold required to create a leaf with a specific area and thickness?
Tip: Always double-check unit conversions, especially when dealing with very small or very large values.
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Math Problem Analysis
Mathematical Concepts
Volume
Density
Geometry
Unit Conversion
Formulas
Volume = Mass / Density
Volume = Area * Thickness
Area = Volume / Thickness
Cross-sectional Area of Cylinder = π * r^2
Volume = Cross-sectional Area * Length
Length = Volume / Cross-sectional Area
Theorems
Volume-Density Relationship
Geometric Volume Formulas
Suitable Grade Level
Grades 10-12
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