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To calculate the mass of the zebra, we can use the kinetic energy formula:

\[
KE = \frac{1}{2}mv^2
\]

Where:
- \( KE \) is the kinetic energy (96,000 J),
- \( m \) is the mass of the zebra (what we want to find),
- \( v \) is the velocity of the zebra (15 m/s).

Rearranging the formula to solve for mass \( m \):

\[
m = \frac{2 \cdot KE}{v^2}
\]

Now, let’s calculate the mass of the zebra.

\[
m = \frac{2 \cdot 96000}{(15)^2}
\]The mass of the zebra is approximately **853 kg** when rounded to two significant figures.

Would you like any more details or have further questions on this?

Here are 5 related questions for further exploration:
1. How would the mass change if the velocity was increased to 20 m/s?
2. What is the relationship between velocity and kinetic energy?
3. If the zebra slowed down to 10 m/s, what would its kinetic energy be?
4. How does the kinetic energy formula apply to objects at rest?
5. What other forms of energy might the zebra have while running?

**Tip:** Remember that kinetic energy is directly proportional to the square of the velocity—small changes in speed can significantly impact the energy stored!

A zebra runs at a speed of 15 m/s and stores 96,000 J of kinetic energy. Calculate the mass of the zebra in kg, giving your answer to 2 significant figures.

Learn how to calculate the mass of a zebra running at 15 m/s with 96,000 J of kinetic energy. This problem involves the kinetic energy formula and highlights the relationship between energy, mass, and speed. Suitable for students in Grades 9-12.

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