Math Problem Statement

If you start with 45 million and then add 45 million every 4 years, how many years would it take to get to 1.6 billion?

Solution

To solve this problem, we can set up a mathematical equation.

You start with 45 million and add 45 million every 4 years. The total amount TT after nn periods of 4 years can be expressed as:

T=45 million+45 million×nT = 45 \text{ million} + 45 \text{ million} \times n

where nn is the number of 4-year periods.

We want to find out when TT reaches 1.6 billion:

45 million+45 million×n=1.6 billion45 \text{ million} + 45 \text{ million} \times n = 1.6 \text{ billion}

First, let's convert everything to millions for simplicity:

45+45n=160045 + 45n = 1600

Next, subtract 45 from both sides:

45n=16004545n = 1600 - 45 45n=155545n = 1555

Now, divide by 45:

n=15554534.56n = \frac{1555}{45} \approx 34.56

So, it would take about 34.56 periods of 4 years each to reach 1.6 billion.

Finally, multiply by 4 to convert the number of periods into years:

Years=34.56×4138.24\text{Years} = 34.56 \times 4 \approx 138.24

Thus, it would take approximately 138 years to reach 1.6 billion.

Would you like further details on this solution or have any additional questions? Here are some related questions:

  1. How would the time change if the initial amount was different?
  2. What would be the total after 50 years?
  3. How many years would it take to reach 1 billion instead of 1.6 billion?
  4. What if the addition amount was increased to 60 million every 4 years?
  5. How does the result change if the addition is every 3 years instead of 4?

Tip: When solving similar problems, it's helpful to convert all numbers to the same unit to simplify calculations.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Progression
Linear Equations

Formulas

Arithmetic progression formula: a_n = a + (n-1) * d

Theorems

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Suitable Grade Level

High School