A 433-kg pile driver is raised 11.8 m above ground.
How much work must be done to raise the pile driver?

The work done to raise an object is given by the equation for gravitational potential energy:

\[
W = mgh
\]

Where:
- \(W\) is the work done,
- \(m\) is the mass of the object (433 kg),
- \(g\) is the acceleration due to gravity (approximately \(9.8 \, \text{m/s}^2\)),
- \(h\) is the height (11.8 m).

Now we can calculate:

\[
W = 433 \times 9.8 \times 11.8
\]

\[
W = 50093.72 \, \text{J} \, (\text{Joules})
\]

So, the work done to raise the pile driver is approximately **50,094 Joules**.

Would you like more details or have any questions? Here are some related questions for further understanding:

1. How would the work change if the pile driver’s mass was doubled?
2. What is the work required if the height is increased by 5 meters?
3. How does gravitational potential energy change if the pile driver is dropped from this height?
4. What is the power needed to lift the pile driver in 5 seconds?
5. How does the work required compare to the kinetic energy of the pile driver if it falls back down?

**Tip:** Always remember that work is energy transferred to an object, especially when lifting against gravity!

A 433-kg pile driver is raised 11.8 m above ground. How much work must be done to raise the pile driver?

Learn how to calculate the work required to raise a 433-kg pile driver 11.8 meters above the ground. This problem uses the gravitational potential energy formula (W = mgh) and covers concepts in physics related to work and energy. Suitable for students in Grades 9-12.

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