A sled is pulled along a level path through snow by a rope. A 30-lb force acting at an angle of 35° above the horizontal moves the sled 60 ft. Find the work done by the force. (Round your answer to the nearest whole number.)

To calculate the work done by the force, we can use the formula:

\[
\text{Work} = F \cdot d \cdot \cos(\theta)
\]

Where:
- \( F \) is the force applied (30 lb)
- \( d \) is the distance moved (60 ft)
- \( \theta \) is the angle of the force above the horizontal (35°)

First, substitute the given values into the formula:

\[
\text{Work} = 30 \times 60 \times \cos(35^\circ)
\]

Now, let's calculate the cosine of 35° and then find the work done:

\[
\cos(35^\circ) \approx 0.8192
\]

\[
\text{Work} \approx 30 \times 60 \times 0.8192
\]

\[
\text{Work} \approx 1474.56 \text{ ft-lb}
\]

Rounding to the nearest whole number, the work done by the force is approximately **1475 ft-lb**.

Would you like more details or have any questions? 

Here are 5 related questions to explore further:

1. How would the work done change if the angle was 45° instead of 35°?
2. What is the significance of the cosine function in the work calculation?
3. How would the work done be affected if the force was doubled but the distance remained the same?
4. Can work be negative? If so, in what scenarios?
5. What is the difference between work done and energy expended?

**Tip:** When dealing with angles in work calculations, always ensure you use the angle relative to the direction of motion.

Explore how to calculate the work done by a 30-lb force pulling a sled along a level path at an angle of 35° above the horizontal. This problem involves key physics concepts like the Work-Energy Principle and trigonometric functions. Perfect for high school students in Grades 9-12.

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