The problem asks for the weight of a 1,413 kg rover on the surface of Earth's moon, with the answer to be given in kilonewtons (kN) and rounded to three significant digits.

Key facts to use:

• The gravitational acceleration on the Moon is approximately $g_{moon} = 1.62 \, \text{m/s}^2$.
• Weight $W$ is calculated by the formula: $W = m \cdot g$ where:
  • $m$ is the mass of the rover (1,413 kg),
  • $g$ is the acceleration due to gravity on the Moon.

Calculation:

1. Calculate the weight in newtons (N): $W = 1,413 \, \text{kg} \times 1.62 \, \text{m/s}^2 = 2,288.06 \, \text{N}$

2. Convert to kilonewtons (kN): $2,288.06 \, \text{N} = 2.288 \, \text{kN}$

3. Round to three significant digits: The weight of the rover on the Moon is $\boxed{2.29 \, \text{kN}}$.

Would you like a detailed breakdown of any part of the process?

Related questions:

1. How does the gravitational acceleration on the Moon compare to Earth's?
2. What is the weight of the rover on Earth?
3. How would you calculate the weight on other celestial bodies, like Mars?
4. What is the unit "newton" and how is it related to mass and acceleration?
5. How does the mass of an object differ from its weight?

Tip:

Always remember that mass remains constant, but weight depends on the gravitational force at a location.