Math Problem Statement

Calculate the wavelength in meters of electromagnetic radiation that has a frequency of 1.02 × 10⁸ s⁻¹. (c = 3.00 X 10⁸ m/s)

Solution

To calculate the wavelength (λ\lambda) of electromagnetic radiation, we can use the equation:

λ=cf\lambda = \frac{c}{f}

Where:

  • λ\lambda is the wavelength (in meters),
  • cc is the speed of light (3.00×108m/s3.00 \times 10^8 \, \text{m/s}),
  • ff is the frequency of the radiation.

Given: f=1.02×108s1f = 1.02 \times 10^8 \, \text{s}^{-1}

Substitute the given values into the equation:

λ=3.00×108m/s1.02×108s1\lambda = \frac{3.00 \times 10^8 \, \text{m/s}}{1.02 \times 10^8 \, \text{s}^{-1}}

Now, let's calculate:

λ=2.94m\lambda = 2.94 \, \text{m}

Thus, the wavelength of the electromagnetic radiation is 2.94 meters.

Would you like more details on the calculation? Here are 5 related questions to deepen your understanding:

  1. What is the relationship between wavelength and frequency in electromagnetic radiation?
  2. How does the speed of light affect the wavelength of radiation at different frequencies?
  3. What type of electromagnetic radiation has a frequency of 1.02×108s11.02 \times 10^8 \, \text{s}^{-1}?
  4. How would the wavelength change if the frequency were doubled?
  5. Can wavelength be measured directly, or is it always calculated from frequency?

Tip: Frequency and wavelength are inversely related, meaning that higher frequencies correspond to shorter wavelengths, and vice versa.

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Math Problem Analysis

Mathematical Concepts

Electromagnetic Radiation
Wave-Particle Duality
Wavelength and Frequency Relationship

Formulas

λ = c / f (Wavelength formula where λ is wavelength, c is the speed of light, and f is the frequency)

Theorems

Inverse relationship between frequency and wavelength in the electromagnetic spectrum

Suitable Grade Level

Grades 9-12