This image represents a transformer circuit with two inductors, where:

• The left side shows the primary winding with a current source labeled $20\angle 0^\circ \, A$.
• The right side shows the secondary winding with an output voltage labeled $V_{\text{out}}$.

To find $V_{\text{out}}$, we typically use the transformer voltage-current relationship. Assuming it’s an ideal transformer, the primary and secondary sides are related by the turns ratio $N_1 : N_2$.

If we denote:

• $N_1$ as the number of turns on the primary coil,
• $N_2$ as the number of turns on the secondary coil,

Then, the output voltage $V_{\text{out}}$ is related to the primary current $I_1$ by:

$V_{\text{out}} = j \omega M I_1$

where:

• $j$ represents the phase shift of 90 degrees due to the mutual inductance.
• $\omega$ is the angular frequency of the current.
• $M$ is the mutual inductance given by $M = k \sqrt{L_1 L_2}$, where $k$ is the coupling coefficient (close to 1 for an ideal transformer).

If we don’t have details on $N_1$ and $N_2$, or $\omega$ and $M$, we’d need them to complete this calculation. Could you provide these values if available?

Let me know if you’d like a detailed solution based on assumptions, or feel free to ask any questions. Here are five related questions:

1. What is the role of turns ratio in transformer voltage calculations?
2. How does mutual inductance affect $V_{\text{out}}$?
3. What are typical values of coupling coefficient $k$ in transformers?
4. How does the frequency of $I_1$ impact the transformer output voltage?
5. How can we calculate $M$ if $k$, $L_1$, and $L_2$ are known?

Tip: Ideal transformers preserve power between the primary and secondary sides, meaning $P_{\text{primary}} = P_{\text{secondary}}$.