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Each question must be rounded to 1 decimal place and have the correct units.
 
a.     The hemisphere has a radius of 10 cm (3 marks)

To solve the problem for the hemisphere with a radius of 10 cm, we need to find some specific properties, likely related to surface area and volume. Let's calculate them step by step:

### a. Volume of the Hemisphere
The formula for the volume of a hemisphere is:
\[
V = \frac{2}{3} \pi r^3
\]
Where \( r = 10 \) cm.

\[
V = \frac{2}{3} \times \pi \times (10)^3 \text{ cm}^3
\]

\[
V = \frac{2}{3} \times \pi \times 1000 \text{ cm}^3
\]

\[
V \approx \frac{2}{3} \times 3.1416 \times 1000 \text{ cm}^3
\]

\[
V \approx \frac{2000}{3} \times 3.1416 \text{ cm}^3
\]

\[
V \approx 2094.4 \text{ cm}^3
\]

So, the volume of the hemisphere is approximately **2094.4 cm³**.

### b. Surface Area of the Hemisphere
The surface area of a hemisphere includes both the curved surface and the base. The formula is:
\[
A = 2 \pi r^2
\]
Where \( r = 10 \) cm.

\[
A = 2 \times \pi \times (10)^2 \text{ cm}^2
\]

\[
A = 2 \times \pi \times 100 \text{ cm}^2
\]

\[
A = 200 \times \pi \text{ cm}^2
\]

\[
A \approx 200 \times 3.1416 \text{ cm}^2
\]

\[
A \approx 628.3 \text{ cm}^2
\]

So, the surface area of the hemisphere is approximately **628.3 cm²**.

Would you like more details or have any questions about this problem?

Here are 5 relative questions to consider:
1. What would the volume be if the radius were doubled?
2. How does the surface area change if the radius is increased by 50%?
3. What is the ratio of the volume of this hemisphere to a full sphere with the same radius?
4. How would the calculations change if the hemisphere were hollow with a certain thickness?
5. What is the lateral (curved) surface area of the hemisphere, excluding the base?

**Tip:** Always keep track of units when performing calculations. It helps prevent errors and ensures your answers are in the correct form.

Learn how to calculate the volume and surface area of a hemisphere with a radius of 10 cm. Step-by-step solution including the volume formula V = (2/3)πr³ and surface area formula A = 2πr². Suitable for high school students.

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