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The image presents a problem asking for the volume of a rectangular shipping box in cubic yards. The given dimensions are:

- Length = \( \frac{1}{4} \) yard
- Width = \( \frac{1}{4} \) yard
- Height = \( \frac{1}{2} \) yard

The volume \( V \) of a rectangular box is calculated using the formula:

\[
V = \text{Length} \times \text{Width} \times \text{Height}
\]

Substituting the given dimensions:

\[
V = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{2} = \frac{1}{16} \times \frac{1}{2} = \frac{1}{32} \, \text{cubic yards}
\]

Thus, the volume of the box is \( \frac{1}{32} \, \text{yd}^3 \).

Would you like more details or have any questions?

Here are 5 related questions to expand on this:

1. How would the volume change if the length doubled?
2. What if the width increased to \( \frac{1}{2} \) yard instead?
3. Can you calculate the surface area of the box using the same dimensions?
4. What are the steps to convert cubic yards to cubic feet?
5. How can you use this volume formula for irregular shapes?

**Tip:** Always remember to keep units consistent when calculating volume, especially with different units like yards and feet.

A shipping box has the dimensions shown. What is the volume of the box in cubic yards?

Learn how to calculate the volume of a rectangular shipping box with dimensions in fractional yards. The problem involves multiplying fractions to find the total volume in cubic yards, perfect for students in Grades 6-8.

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