What is the volume of a sphere with a diameter of 43.5 cm, rounded to the *nearest tenth* of a cubic centimeter?

To find the volume of a sphere, we use the formula:

\[
V = \frac{4}{3} \pi r^3
\]

Where:
- \(V\) is the volume,
- \(r\) is the radius, which is half of the diameter.

Given that the diameter is 43.5 cm, we can calculate the radius as:

\[
r = \frac{43.5}{2} = 21.75 \text{ cm}
\]

Now, substituting the radius into the formula for volume:

\[
V = \frac{4}{3} \pi (21.75)^3
\]

Let's calculate this.

\[
V = \frac{4}{3} \times 3.1416 \times (21.75)^3 \approx 43058.5 \text{ cubic centimeters}
\]

Rounding to the nearest tenth, the volume is approximately:

\[
V \approx 43058.5 \text{ cm}^3
\]

Would you like more details on the calculation?

Here are 5 related questions to explore further:
1. What is the surface area of the sphere with the same diameter?
2. How would the volume change if the diameter was doubled?
3. What is the relationship between the radius and the volume of a sphere?
4. How do you calculate the volume of a hemisphere?
5. What are some real-life applications of the sphere volume formula?

**Tip:** Always ensure you use the correct units when calculating volume or area.

What is the volume of a sphere with a diameter of 43.5 cm, rounded to the nearest tenth of a cubic centimeter?

Learn how to calculate the volume of a sphere with a diameter of 43.5 cm. This problem demonstrates the use of the volume of a sphere formula (V = 4/3 π r^3), yielding an approximate result of 43058.5 cubic centimeters, rounded to the nearest tenth.

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