acetone, the solvent in many nail polish removers, has a density of .791 g/ml. Calculate the volume, in milliliters, of 15.2 g of acetone.

To calculate the volume of acetone given its mass and density, you can use the formula:

\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]

Where:
- Mass = 15.2 g
- Density = 0.791 g/mL

Substitute the values into the formula:

\[
\text{Volume} = \frac{15.2 \, \text{g}}{0.791 \, \text{g/mL}} = 19.21 \, \text{mL}
\]

Thus, the volume of 15.2 g of acetone is approximately **19.21 mL**.

Would you like more details or have any questions? 

Here are 5 related questions to deepen your understanding:
1. How would the volume change if the mass of acetone was doubled?
2. What would happen to the volume if the density of the solvent increased?
3. How can we calculate the mass of acetone if the volume and density are known?
4. Can you explain the concept of density in relation to other common solvents?
5. What is the formula for converting mass to volume for any substance?

**Tip**: Always ensure that the units are consistent when using formulas (e.g., mass in grams, volume in mL).

Acetone, the solvent in many nail polish removers, has a density of 0.791 g/mL. Calculate the volume, in milliliters, of 15.2 g of acetone.

Learn how to calculate the volume of 15.2 g of acetone given its density of 0.791 g/mL. This step-by-step solution explains the formula for volume calculation using mass and density, ideal for students in Grades 8-10.

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