Math Problem Statement

acetone, the solvent in many nail polish removers, has a density of .791 g/ml. Calculate the volume, in milliliters, of 15.2 g of acetone.

Solution

To calculate the volume of acetone given its mass and density, you can use the formula:

Volume=MassDensity\text{Volume} = \frac{\text{Mass}}{\text{Density}}

Where:

  • Mass = 15.2 g
  • Density = 0.791 g/mL

Substitute the values into the formula:

Volume=15.2g0.791g/mL=19.21mL\text{Volume} = \frac{15.2 \, \text{g}}{0.791 \, \text{g/mL}} = 19.21 \, \text{mL}

Thus, the volume of 15.2 g of acetone is approximately 19.21 mL.

Would you like more details or have any questions?

Here are 5 related questions to deepen your understanding:

  1. How would the volume change if the mass of acetone was doubled?
  2. What would happen to the volume if the density of the solvent increased?
  3. How can we calculate the mass of acetone if the volume and density are known?
  4. Can you explain the concept of density in relation to other common solvents?
  5. What is the formula for converting mass to volume for any substance?

Tip: Always ensure that the units are consistent when using formulas (e.g., mass in grams, volume in mL).

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Math Problem Analysis

Mathematical Concepts

Density and Volume Calculation
Algebra

Formulas

Volume = Mass / Density

Theorems

Basic Density-Volume Relationship

Suitable Grade Level

Grades 8-10