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The image contains the following problem in Italian:

**Problem:**
"Una lastra di alluminio è larga 35 cm, lunga 11 dm e spessa 15 mm.
- Esprimi queste dimensioni in metri.
- Determina poi il volume e la massa della lastra in unità SI (cerca nel testo il dato di cui hai bisogno)."

Let's break it down and solve the problem:

1. **Convert the dimensions to meters:**
   - **Width:** 35 cm = 0.35 meters (since 1 cm = 0.01 meters)
   - **Length:** 11 dm = 1.1 meters (since 1 dm = 0.1 meters)
   - **Thickness:** 15 mm = 0.015 meters (since 1 mm = 0.001 meters)

2. **Determine the volume:**
   The volume \( V \) of the aluminum sheet can be calculated as:
   \[
   V = \text{width} \times \text{length} \times \text{thickness}
   \]
   Substituting the values:
   \[
   V = 0.35 \, \text{m} \times 1.1 \, \text{m} \times 0.015 \, \text{m} = 0.005775 \, \text{m}^3
   \]

3. **Determine the mass:**
   To find the mass, we need the density of aluminum. The density of aluminum is approximately \( 2.7 \, \text{g/cm}^3 \) or \( 2700 \, \text{kg/m}^3 \).

   The mass \( m \) is calculated by the formula:
   \[
   m = \text{density} \times \text{volume}
   \]
   Substituting the values:
   \[
   m = 2700 \, \text{kg/m}^3 \times 0.005775 \, \text{m}^3 = 15.5925 \, \text{kg}
   \]

   Therefore, the mass of the aluminum sheet is approximately **15.6 kg**.

---

Do you need any further details or explanations? Here are five related questions to explore:

1. How would the result change if the sheet were made of a different material, like steel?
2. What is the significance of converting units to the SI system in physics and engineering?
3. How would you approach this problem if the sheet had a different shape, like a cylinder?
4. What are some common applications where knowing the mass of materials is crucial?
5. How can density vary between different types of aluminum alloys?

**Tip:** Always ensure that all units are consistent before performing calculations. This avoids errors in determining physical quantities like volume or mass.

Una lastra di alluminio è larga 35 cm, lunga 11 dm e spessa 15 mm. Esprimi queste dimensioni in metri. Determina poi il volume e la massa della lastra in unità SI.

Learn how to calculate the volume and mass of an aluminum sheet using given dimensions: 35 cm wide, 11 dm long, and 15 mm thick. Follow the unit conversions to meters and apply the formula for volume and mass calculation based on aluminum's density.

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