Math Problem Statement

A cylinder has a circular base with an area of 40 cm2 and a height of 60 cm. Determine the volume of a cone that has five times the radius and six times the height of the cylinder.

Solution

To solve the problem, let's break it down step-by-step. We need to find the volume of a cone with specific dimensions relative to a given cylinder.

Step 1: Analyze the cylinder

We know:

  • The area of the circular base of the cylinder AbaseA_{\text{base}} is 40cm240 \, \text{cm}^2.
  • The height of the cylinder hcylinderh_{\text{cylinder}} is 60cm60 \, \text{cm}.

Step 2: Find the radius of the cylinder

The area of the circular base of a cylinder is given by the formula: Abase=πr2A_{\text{base}} = \pi r^2

Given Abase=40cm2A_{\text{base}} = 40 \, \text{cm}^2: πr2=40\pi r^2 = 40 r2=40πr^2 = \frac{40}{\pi} r=40πr = \sqrt{\frac{40}{\pi}}

Step 3: Determine the dimensions of the cone

The problem states that the cone has:

  • Five times the radius of the cylinder.
  • Six times the height of the cylinder.

Let's calculate these: rcone=5rr_{\text{cone}} = 5r hcone=6hcylinderh_{\text{cone}} = 6h_{\text{cylinder}}

First, compute the radius of the cone: rcone=5×40πr_{\text{cone}} = 5 \times \sqrt{\frac{40}{\pi}} rcone=540πr_{\text{cone}} = 5 \sqrt{\frac{40}{\pi}}

Next, compute the height of the cone: hcone=6×60cm=360cmh_{\text{cone}} = 6 \times 60 \, \text{cm} = 360 \, \text{cm}

Step 4: Find the volume of the cone

The volume VconeV_{\text{cone}} of a cone is given by the formula: Vcone=13πrcone2hconeV_{\text{cone}} = \frac{1}{3} \pi r_{\text{cone}}^2 h_{\text{cone}}

Substitute the values for rconer_{\text{cone}} and hconeh_{\text{cone}}: Vcone=13π(540π)2×360V_{\text{cone}} = \frac{1}{3} \pi \left(5 \sqrt{\frac{40}{\pi}}\right)^2 \times 360

Simplify inside the square: (540π)2=25(40π)=1000π\left(5 \sqrt{\frac{40}{\pi}}\right)^2 = 25 \left(\frac{40}{\pi}\right) = \frac{1000}{\pi}

Now substitute back: Vcone=13π(1000π)×360V_{\text{cone}} = \frac{1}{3} \pi \left(\frac{1000}{\pi}\right) \times 360

Simplify further: Vcone=13×1000×360V_{\text{cone}} = \frac{1}{3} \times 1000 \times 360 Vcone=3600003V_{\text{cone}} = \frac{360000}{3} Vcone=120000cm3V_{\text{cone}} = 120000 \, \text{cm}^3

Thus, the volume of the cone is 120,000 cubic centimeters (cm³).

Would you like more details on any specific part of the calculation, or do you have any other questions?

Here are some related questions to expand your understanding:

  1. How do you find the surface area of a cone with the same dimensions?
  2. What is the volume of the original cylinder?
  3. How does changing the height of a cone affect its volume?
  4. How do you calculate the lateral surface area of a cone?
  5. What is the formula for the volume of a cylinder and how is it derived?
  6. How does the volume of a cylinder compare to that of a cone with the same base and height?
  7. What are the properties of similar geometric shapes?
  8. How do you derive the formula for the volume of a cone?

Tip

When working with composite shapes or transforming one shape into another (like a cylinder to a cone), always pay attention to the relationship between their dimensions and how it affects volume or surface area calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Volume Calculation

Formulas

Volume of a Cone

Theorems

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Suitable Grade Level

Grades 9-12