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To solve this problem, we need to break it down into steps. The key is to calculate the virtual metacentric height (GM) for the vessel *M.V. Indian Pride* under the given conditions:

### Given:
- Length of the vessel = 140 m
- Forward draft (TF) = 4 m
- Aft draft (TA) = 6 m
- KG (Vertical center of gravity) = 8.3 m
- Water level has dropped by 1 meter after the stern has taken the blocks.

From the hydrostatic table, we can extract the necessary information for different drafts. Since the water level drops by 1 meter, we'll likely be working with a new draft value after the drop.

Now, let's outline the process:

### 1. Find the initial mean draft.
The mean draft before the water level drops is:
\[
\text{Mean Draft} = \frac{T_F + T_A}{2} = \frac{4 + 6}{2} = 5 \, \text{m}
\]

### 2. Find displacement, KM, and other parameters for the initial mean draft of 5.0 m.
From the table:
- Displacement at draft 5.0 m = 9891 t
- KM at draft 5.0 m = 8.686 m

### 3. Determine the new mean draft after the 1 m water level drop.
The new mean draft will be:
\[
\text{New Mean Draft} = \text{Mean Draft} - 1 \, \text{m} = 5.0 - 1 = 4.0 \, \text{m}
\]

### 4. Find displacement and KM for the new mean draft.
From the table, no direct value is available for a 4.0 m draft. However, we can approximate or extrapolate between the given values (4.6 m and 4.8 m) if necessary, or use the closest available data (4.6 m) for simplicity.

At a draft of 4.6 m:
- Displacement = 9013 t
- KM = 8.992 m

### 5. Calculate the change in displacement.
The change in displacement is:
\[
\Delta \text{Displacement} = 9891 - 9013 = 878 \, \text{t}
\]

### 6. Calculate the moment to change trim (MCTC) and the new trim.
The MCTC (moment to change trim by 1 cm) for a 5.0 m draft is 165.7 tm/cm, and the LCF (longitudinal center of flotation) is 71.913 m. 

We would use the MCTC and trim calculations if we needed to further analyze the effect of the water level change on stability.

### 7. Calculate the virtual GM.
The virtual GM (metacentric height) can be found using the formula:
\[
\text{Virtual GM} = KM - KG
\]
Using the KM after the water level drop (for the draft of 4.6 m):
\[
\text{Virtual GM} = 8.992 - 8.3 = 0.692 \, \text{m}
\]

Thus, the **virtual GM** after the water level has dropped by 1 meter is **0.692 meters**.

### Would you like further details or have any questions?

### Related questions:
1. What is the significance of metacentric height (GM) in ship stability?
2. How does the change in water level affect a ship's stability?
3. What are the differences between initial GM and virtual GM?
4. How can we interpolate values for hydrostatic tables that don't directly match the needed draft?
5. How would the GM change if the KG were lower or higher?

#### Tip:
Always ensure to properly interpolate data from hydrostatic tables if the exact draft values aren't available to maintain accuracy in ship stability calculations.

M.V. Indian Pride 140 m long enters a SW drydock drawing 4 m fwd and 6 m aft. KG = 8.3 m. Find the virtual GM when the water level has dropped by 1 m after the stern has taken to the blocks.

This page provides a step-by-step solution to calculate the virtual metacentric height (GM) of M.V. Indian Pride after a 1-meter water level drop in a drydock. The solution involves calculating mean draft, displacement changes, and using the hydrostatic table data. Suitable for marine engineering students.

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