We can find the vehicle's acceleration using the kinematic equation that relates velocity, displacement, and acceleration:

$v^2 = u^2 + 2a s$

Where:

• $v$ is the final velocity (30 m/s),
• $u$ is the initial velocity (0 m/s),
• $a$ is the acceleration (what we're solving for),
• $s$ is the displacement (60 m).

Now, plugging in the known values:

$(30)^2 = (0)^2 + 2 \cdot a \cdot 60$

This simplifies to:

$900 = 120a$

Now, solve for $a$:

$a = \frac{900}{120} = 7.5 \, \text{m/s}^2$

So, the vehicle's acceleration is 7.5 m/s².

Would you like more details or have any questions?

Here are some related questions for further practice:

1. What would the acceleration be if the car reached 40 m/s over the same displacement?
2. How long did the car take to reach 30 m/s with this acceleration?
3. If the car maintained this acceleration, what would its velocity be after covering 100 meters?
4. What is the car's displacement if it reaches 30 m/s in 3 seconds?
5. How much time does it take to cover the 60 meters with this acceleration?

Tip: In kinematics, always check the given information carefully to choose the correct equation for the unknown quantity!