how many units are sold at 500. x=-5p+100, R(p)=-5p^2+100p

To find the number of units sold at a price of \( p = 500 \), let's start by analyzing the equation given for the number of units sold, represented by \( x \):

\[
x = -5p + 100
\]

Here:
- \( x \) is the quantity of units sold,
- \( p \) is the price per unit.

### Step 1: Substitute \( p = 500 \) into the equation for \( x \)
Substitute \( p = 500 \) into the equation to find \( x \):

\[
x = -5(500) + 100
\]

### Step 2: Calculate the expression
\[
x = -2500 + 100 = -2400
\]

So, at a price of \( p = 500 \), \( x = -2400 \).

### Interpretation
The negative value here suggests

Discover how to calculate the number of units sold at a price of 500 using the equation x = -5p + 100. This problem includes a detailed substitution process and explores revenue functions, ideal for students in Grades 10-12.

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