Math Problem Statement

The two containers are mathematically similar in shape. The larger container has a volume of 3456 cm³ and a surface area of 1024 cm². The smaller container has a volume of 1458 cm³. Calculate the surface area of the smaller container.

Solution

To solve this problem, we need to use the properties of similar shapes. When two shapes are mathematically similar, the ratios of their corresponding dimensions are equal. Specifically:

  1. The ratio of their volumes is the cube of their linear (scale) ratio.
  2. The ratio of their surface areas is the square of their linear (scale) ratio.

Given:

  • Volume of the larger container, Vlarge=3456cm3V_{\text{large}} = 3456 \, \text{cm}^3
  • Surface area of the larger container, SAlarge=1024cm2SA_{\text{large}} = 1024 \, \text{cm}^2
  • Volume of the smaller container, Vsmall=1458cm3V_{\text{small}} = 1458 \, \text{cm}^3

We need to find the surface area of the smaller container, SAsmallSA_{\text{small}}.

Step-by-Step Solution

  1. Calculate the Volume Ratio:

    Volume Ratio=VsmallVlarge=14583456\text{Volume Ratio} = \frac{V_{\text{small}}}{V_{\text{large}}} = \frac{1458}{3456}

  2. Determine the Linear Scale Factor:

    Since the volume ratio is the cube of the linear ratio kk:

    k3=14583456k^3 = \frac{1458}{3456}

    Solving for kk (the linear scale factor):

    k=145834563k = \sqrt[3]{\frac{1458}{3456}}

  3. Calculate the Surface Area Ratio:

    The surface area ratio is k2k^2, so once we have kk, we can calculate k2k^2 and use it to find the surface area of the smaller container:

    SAsmall=SAlarge×k2SA_{\text{small}} = SA_{\text{large}} \times k^2

Let's calculate these values step-by-step:

  1. Calculate 14583456\frac{1458}{3456}.
  2. Take the cube root to find kk.
  3. Square kk to get k2k^2.
  4. Multiply k2k^2 by 1024cm21024 \, \text{cm}^2 to find SAsmallSA_{\text{small}}.

Let's proceed with these calculations.The surface area of the smaller container is 576cm2576 \, \text{cm}^2.

Would you like further details on any part of this solution, or do you have additional questions?

Here are some related questions to explore further:

  1. How would the solution change if only the surface area of the larger container were given?
  2. What if we had the height of the containers instead of volume?
  3. How can similar shape properties help in scaling down architectural models?
  4. What happens to the surface area if the volume of the smaller container is halved?
  5. How can we apply these principles in 3D printing?

Tip: For similar shapes, remember that area scales with the square of the linear ratio, and volume scales with the cube of the linear ratio.

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Math Problem Analysis

Mathematical Concepts

Similar Shapes
Ratios
Proportionality
Geometry

Formulas

Volume Ratio = V_small / V_large
Surface Area Ratio = k^2
k = (Volume Ratio)^(1/3)
SA_small = SA_large * k^2

Theorems

Properties of Similar Shapes

Suitable Grade Level

Grades 10-12