Math Problem Statement
Let π§π=ππ+πππ be a series of complex numbers located on the unit circle. given that π1+π2+β―+π10=2. Let π€π be a series defined by π€π=π§π+1π§π. Calculate the sum of the first ten terms of π€π .
Solution
We are given that is a series of complex numbers located on the unit circle, which implies that for all . The sum of the real parts .
We need to calculate the sum of the first ten terms of the series defined by:
where is the complex conjugate of .
Step 1: Expressing
The complex conjugate of is given by:
So,
Expanding the product:
Since , can be written as , where is the argument of . Therefore, can be written as:
Step 2: Sum of the first ten terms of
We need to calculate:
This sum simplifies as a telescoping series:
Notice that:
Since is on the unit circle, , and hence . Therefore:
Thus, the sum of the first ten terms of is:
So, the sum of the first ten terms of is .
Would you like more details on any of the steps or further exploration? Here are some related questions:
- How does the concept of the unit circle affect the magnitude of complex numbers?
- Can the sum ever be different from 1 under different conditions?
- How does the telescoping series simplify the sum in this problem?
- What is the significance of the argument in complex numbers on the unit circle?
- Can you generalize the result to any number instead of 10?
Tip: When dealing with complex numbers on the unit circle, expressing them in exponential form often simplifies calculations, especially for products and sums.
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Math Problem Analysis
Mathematical Concepts
Complex Numbers
Unit Circle
Telescoping Series
Formulas
Complex conjugate
Theorems
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Suitable Grade Level
Advanced High School
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