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To find the amount of square feet of steel needed to manufacture the spherical water tank, we need to calculate the surface area of a sphere with a given diameter. Here’s how to proceed:

### Given Information:
- **Diameter of the tank** = 49 feet.

### Steps to Solve:
1. **Calculate the Radius**:
   \[
   \text{Radius} = \frac{\text{Diameter}}{2} = \frac{49}{2} = 24.5 \text{ feet}
   \]

2. **Use the Surface Area Formula for a Sphere**:
   The surface area \(A\) of a sphere is given by:
   \[
   A = 4 \pi r^2
   \]
   where \( r \) is the radius.

3. **Substitute and Solve**:
   \[
   A = 4 \pi (24.5)^2
   \]
   Calculating \( (24.5)^2 \):
   \[
   (24.5)^2 = 600.25
   \]
   So,
   \[
   A = 4 \pi \times 600.25
   \]
   \[
   A \approx 4 \times 3.1416 \times 600.25
   \]
   \[
   A \approx 7539.8 \text{ square feet}
   \]

### Answer:
The amount of steel needed is approximately **7539.8 square feet** (rounded to the nearest tenth as required).

Would you like more details or have any questions on this solution?

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Here are some related questions to deepen your understanding:

1. What would the surface area be if the diameter was doubled?
2. How would the surface area formula change if the shape was a cylinder instead of a sphere?
3. What is the formula for the volume of a sphere, and how does it compare to the surface area?
4. How would the calculation change if the radius was given instead of the diameter?
5. If the tank was a hemisphere instead of a full sphere, what would the surface area be?

**Tip:** Always double-check your calculations with the correct values of \(\pi\) and round according to the specified instructions.

How many square feet of steel are needed to manufacture a spherical water tank with a diameter of 49 ft?

Find the square feet of steel needed to manufacture a spherical water tank with a 49 ft diameter. This problem involves calculating the surface area of a sphere using geometry formulas, suitable for high school students (Grades 9-12).

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