Math Problem Statement

Why I am getting below answer ?

Transition to state s′s's′ with probability 0.4, reward R′=10R' = 10R′=10, and v(s′)=0v(s') = 0v(s′)=0 (assumed).

Transition to state s′′s''s′′ with probability 0.6, reward R′′=3R'' = 3R′′=3, and v(s′′)=0v(s'') = 0v(s′′)=0 (assumed).

Discount factor γ=0.5\gamma = 0.5γ=0.5.

Formula:

v(s)=Probability to s′×(R′+γv(s′))+Probability to s′′×(R′′+γv(s′′))v(s) = \text{Probability to } s' \times \left(R' + \gamma v(s')\right) + \text{Probability to } s'' \times \left(R'' + \gamma v(s'')\right)v(s)=Probability to s′×(R′+γv(s′))+Probability to s′′×(R′′+γv(s′′))

Substitute the values:

v(s)=0.4×(10+0.5×0)+0.6×(3+0.5×0)v(s) = 0.4 \times \left(10 + 0.5 \times 0\right) + 0.6 \times \left(3 + 0.5 \times 0\right)v(s)=0.4×(10+0.5×0)+0.6×(3+0.5×0)

Simplify:

v(s)=0.4×(10+0)+0.6×(3+0)v(s) = 0.4 \times (10 + 0) + 0.6 \times (3 + 0)v(s)=0.4×(10+0)+0.6×(3+0) v(s)=0.4×10+0.6×3v(s) = 0.4 \times 10 + 0.6 \times 3v(s)=0.4×10+0.6×3 v(s)=4+1.8v(s) = 4 + 1.8v(s)=4+1.8 v(s)=5.8v(s) = 5.8v(s)=5.8

Thus, the value of state sss is 5.8.

4o mini

Solution

The value you obtained, 5.8, for the state ss is correct given the assumptions you've made. Let's go through your reasoning step-by-step to understand why this value makes sense.

Given Information and Assumptions

  1. Transitions and Rewards:

    • With probability 0.4, the agent transitions to state ss' with reward R=10R' = 10 and v(s)=0v(s') = 0 (assumed).
    • With probability 0.6, the agent transitions to state ss'' with reward R=3R'' = 3 and v(s)=0v(s'') = 0 (assumed).
  2. Discount Factor:

    • γ=0.5\gamma = 0.5.
  3. Formula:

    • The Bellman equation for the expected value of state ss is: v(s)=P(ss)(R+γv(s))+P(ss)(R+γv(s))v(s) = P(s' \mid s) \cdot (R' + \gamma \cdot v(s')) + P(s'' \mid s) \cdot (R'' + \gamma \cdot v(s'')) Given: v(s)=0.4×(10+0.5×0)+0.6×(3+0.5×0)v(s) = 0.4 \times (10 + 0.5 \times 0) + 0.6 \times (3 + 0.5 \times 0)

Calculation

Let's break down the calculation step-by-step:

  1. Substitute the values:

v(s)=0.4×(10+0.5×0)+0.6×(3+0.5×0)v(s) = 0.4 \times (10 + 0.5 \times 0) + 0.6 \times (3 + 0.5 \times 0)

Since v(s)=0v(s') = 0 and v(s)=0v(s'') = 0 by assumption:

v(s)=0.4×(10+0)+0.6×(3+0)v(s) = 0.4 \times (10 + 0) + 0.6 \times (3 + 0)

  1. Simplify the expression:

v(s)=0.4×10+0.6×3v(s) = 0.4 \times 10 + 0.6 \times 3

v(s)=4+1.8v(s) = 4 + 1.8

  1. Compute the final value:

v(s)=5.8v(s) = 5.8

Conclusion

The value of state ss is 5.8.

Why is this the answer?

  • The value 5.85.8 is correct based on the assumption that v(s)=0v(s') = 0 and v(s)=0v(s'') = 0.
  • The calculation uses the probabilities of transitioning to each state and the associated immediate rewards, along with the discount factor and assumed future state values.
  • Since both v(s)v(s') and v(s)v(s'') are assumed to be 0, the contribution from the future discounted values (γv(s)\gamma \cdot v(s') and γv(s)\gamma \cdot v(s'')) is also 0.

Questions for Further Exploration

  1. What happens to the value v(s)v(s) if we change the assumed values of v(s)v(s') and v(s)v(s'')?
  2. How does changing the discount factor γ\gamma affect the value v(s)v(s)?
  3. What if the transition probabilities to ss' and ss'' were different? How would that impact v(s)v(s)?
  4. What role do immediate rewards play in determining the value of a state in an MDP?
  5. Can you calculate the value of ss using different assumed values for v(s)v(s') and v(s)v(s'')?

Tip

In reinforcement learning, the value of a state represents the expected return (cumulative future rewards) the agent can obtain starting from that state. Always check the assumptions (like values of v(s)v(s') and v(s)v(s'')) to understand their impact on the calculation.

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Math Problem Analysis

Mathematical Concepts

Markov Decision Process
Bellman Equation

Formulas

Bellman equation for state value

Theorems

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Suitable Grade Level

Advanced