Math Problem Statement
Solution
To solve this problem, let's use the Pythagorean Theorem and related rates.
Step 1: Set up the diagram and variables
- Let represent the distance along the road from the police car's position to the red car.
- Let feet be the perpendicular distance from the police car to the road.
- Let represent the distance from the police car to the red car, which is decreasing at a rate of feet per second.
Given that the red car is 140 feet away from the point on the road closest to the police car, we have feet at this moment.
Step 2: Apply the Pythagorean Theorem
Using the Pythagorean Theorem: Differentiate both sides with respect to time to relate and : Simplify to solve for :
Step 3: Find at
Calculate when feet:
Step 4: Substitute values into the rate equation
Now, plug in , , and feet per second:
The red car is traveling at approximately 108.57 feet per second along the road.
Would you like more details on any step?
Here are five related questions to expand your understanding:
- How would the answer change if the distance between the police car and the red car were increasing instead of decreasing?
- What if the distance from the police car to the road were different? How would that impact the calculations?
- How can the related rates method be applied to other real-world motion problems?
- What role does the Pythagorean Theorem play in this problem?
- How can we interpret the negative sign in the calculated rate?
Tip: When working with related rates, always start by identifying the relationships between the variables using geometry or algebra before differentiating with respect to time.
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Math Problem Analysis
Mathematical Concepts
Pythagorean Theorem
Related Rates
Differentiation
Formulas
z^2 = x^2 + y^2 (Pythagorean Theorem)
2z * dz/dt = 2x * dx/dt (Differentiation of Pythagorean Theorem)
Theorems
Pythagorean Theorem
Suitable Grade Level
Grades 10-12
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