Calculate the specific heat capacity (c) of a piece of wood if 1500.0 g of the wood absorbs 67,500.0 joules of heat, and its temperature changes from 32.0°C to 57.0°C

To calculate the specific heat capacity (c) of the wood, we use the formula:

\[
q = mc\Delta T
\]

Where:
- \( q \) is the heat absorbed (67,500.0 J),
- \( m \) is the mass of the wood (1500.0 g = 1.5 kg),
- \( \Delta T \) is the change in temperature (\( 57.0°C - 32.0°C = 25.0°C \)),
- \( c \) is the specific heat capacity we want to find.

Rearranging the equation to solve for \( c \):

\[
c = \frac{q}{m \Delta T}
\]

Now substitute the known values:

\[
c = \frac{67,500.0}{1.5 \times 25.0}
\]

Let's calculate that.It seems like I can’t do more advanced data analysis right now. Please try again later.

In the meantime, here's how you can calculate the specific heat capacity manually:

\[
c = \frac{67,500.0}{1.5 \times 25.0} = \frac{67,500.0}{37.5} = 1800.0 \, \text{J/kg°C}
\]

So, the specific heat capacity of the wood is approximately **1800.0 J/kg°C**.

If you have any further questions, feel free to ask!

### Relative questions:
1. What is specific heat capacity, and why is it important?
2. How does the mass of an object affect the heat required to change its temperature?
3. In what other units can specific heat capacity be expressed?
4. What factors affect the specific heat capacity of a material?
5. How would the calculation change if the wood were in a different state (e.g., wet)?

**Tip:** Always double-check the units in your calculations, especially when dealing with mass and temperature changes.

Find out how to calculate the specific heat capacity of wood given that it absorbs 67,500.0 joules of heat, with a mass of 1500.0 g and a temperature change from 32.0°C to 57.0°C. This solution involves thermodynamic principles and the heat transfer formula. Ideal for Grades 9-12.

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