The graph you've provided shows a straight line and asks for the slope, using the $y$-intercept and the highlighted dot.

Step 1: Identify key points

• The y-intercept occurs where the line crosses the $y$-axis. From the graph, this is at $(0, -400)$.
• The highlighted point is located at approximately $(60, 1200)$.

Step 2: Calculate the slope

The formula for slope $m$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Here:

• $(x_1, y_1) = (0, -400)$
• $(x_2, y_2) = (60, 1200)$

Substitute the values into the formula:

$m = \frac{1200 - (-400)}{60 - 0} = \frac{1200 + 400}{60} = \frac{1600}{60} \approx 26.67$

So, the slope of the line is approximately 26.67.

Let me know if you would like further clarification or details! Here are some related questions:

1. How does the slope affect the steepness of the line?
2. What does a positive slope indicate about the direction of the line?
3. Can the slope be zero? What would that look like?
4. How would you calculate the slope if given two points with different coordinates?
5. What would happen to the slope if the points were reversed?

Tip: Always check the coordinates of key points (such as the y-intercept and a specific point) carefully when calculating the slope.