Math Problem Statement

Mateo’s sister paid off her student loan of $5000 in 3 years. If she made a payment of $152.35 each month, what was the simple interest rate for her loan? Round to the nearest hundredth.

Solution

We are asked to determine the simple interest rate for a student loan.

Given:

  • Loan amount P=5000P = 5000 dollars
  • Time period t=3t = 3 years
  • Monthly payment PMT=152.35PMT = 152.35 dollars
  • Total payments made 152.35×12×3152.35 \times 12 \times 3

Total Amount Paid:

Total Amount Paid=152.35×12×3=5484.60 dollars\text{Total Amount Paid} = 152.35 \times 12 \times 3 = 5484.60 \text{ dollars}

Interest Paid:

The interest paid is the total amount paid minus the principal: I=5484.605000=484.60 dollarsI = 5484.60 - 5000 = 484.60 \text{ dollars}

Formula for Simple Interest:

The simple interest formula is: I=P×r×tI = P \times r \times t where:

  • II is the interest paid
  • PP is the principal (loan amount)
  • rr is the annual interest rate
  • tt is the time in years

Now, solve for rr: r=IP×t=484.605000×3=484.6015000=0.03231r = \frac{I}{P \times t} = \frac{484.60}{5000 \times 3} = \frac{484.60}{15000} = 0.03231

Final Result:

The simple interest rate is approximately 3.23%3.23\%.

Would you like further details on any steps?

Related questions:

  1. What is the difference between simple and compound interest?
  2. How would the monthly payment change if the loan term was 5 years instead of 3?
  3. How do you calculate the interest if the rate is compounded annually?
  4. How would the interest change if the loan was $10,000 instead of $5,000?
  5. How does the interest rate affect the total amount paid on a loan?

Tip:

When calculating interest, always ensure the time units for rate and loan term are consistent (e.g., both in years).

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Math Problem Analysis

Mathematical Concepts

Simple Interest
Loan Payment
Algebra

Formulas

Total Amount Paid = Monthly Payment × 12 × Number of Years
Interest Paid = Total Amount Paid - Principal
Simple Interest Formula: I = P × r × t

Theorems

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Suitable Grade Level

Grades 10-12