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Let's go through the steps for this problem:

**Problem Breakdown:**
- A doll is regularly priced at **$13**.
- For a sale, the price is **reduced by 55%**.

### Part (a):
You need to set up a proportion that represents the reduction in price.

### Part (b):
We use the proportion from part (a) to find the reduction in price.

The reduction is 55% of the original price. So, you can set up the proportion like this:

\[
\frac{\text{Reduction in price}}{\text{Original price}} = \frac{55}{100}
\]

\[
\frac{x}{13} = \frac{55}{100}
\]

Now, cross-multiply to solve for $x$:

\[
100x = 13 \times 55
\]

\[
100x = 715
\]

\[
x = \frac{715}{100} = 7.15
\]

So, the **reduction in price** is **$7.15**.

### Part (c):
Now, to find the **sale price**, subtract the reduction from the original price:

\[
13 - 7.15 = 5.85
\]

So, the **price during the sale** is **$5.85**.

---

Would you like further details or any clarification?

Here are 5 related questions to deepen your understanding:

1. How would the price reduction change if the discount were 60% instead of 55%?
2. If the original price was $20, how much would the reduction be with a 55% discount?
3. What would the sale price be if the reduction percentage were 45% instead?
4. How would you set up a proportion for a 30% discount on a $50 item?
5. Can you calculate the percentage discount if the reduction is $6.50 on an original price of $20?

**Tip:** When solving percentage problems, always remember that "percentage" means per hundred, making proportions an effective method for solving them.

A doll is regularly priced at $13. For a sale, the price was reduced by 55%. (a) Create a proportion that can be used to find the reduction in price. (b) Use the proportion from part (a) to find the reduction in price. (c) What was the price of the doll during the sale?

Learn how to calculate the reduction in price and the sale price of a doll originally priced at $13 with a 55% discount. This problem covers concepts of proportions, percentage calculations, and basic arithmetic. Suitable for middle school students in Grades 6-8.

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