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To solve the problem presented in the image, we need to calculate the total resultant hydrostatic force acting on the vertical side of the tank (side ABCD), and the location of the center of pressure.

### Step-by-step approach:

1. **Given Data:**
   - Height of water: 2 m
   - Width of side ABCD: 6 m (from A to B)
   - Depth of the tank (perpendicular to side ABCD): 2.5 m (from A to D)
   - Water density \(\rho = 1000 \, \text{kg/m}^3\) (assuming standard conditions)
   - Acceleration due to gravity \(g = 9.81 \, \text{m/s}^2\)

2. **Hydrostatic Pressure on a Vertical Surface:**
   Hydrostatic pressure \(P\) at a depth \(h\) below the water surface is given by:
   \[
   P(h) = \rho g h
   \]

3. **Resultant Hydrostatic Force \(F\):**
   The total force exerted on a vertical submerged surface is the integral of the pressure over the surface area.
   \[
   F = \rho g A \bar{h}
   \]
   where:
   - \(A\) is the area of the surface (width × depth)
   - \(\bar{h}\) is the depth to the centroid of the surface, which for a vertical rectangle is half the height, i.e., \(\bar{h} = \frac{2}{2} = 1 \, \text{m}\).

   The area \(A\) of the side ABCD is:
   \[
   A = 6 \, \text{m} \times 2.5 \, \text{m} = 15 \, \text{m}^2
   \]

   The total resultant force \(F\) is then:
   \[
   F = 1000 \, \text{kg/m}^3 \times 9.81 \, \text{m/s}^2 \times 15 \, \text{m}^2 \times 1 \, \text{m}
   \]
   Let me compute this value.

4. **Location of the Center of Pressure:**
   The center of pressure for a vertically submerged surface is located below the centroid at a depth \(h_{\text{cp}}\) given by:
   \[
   h_{\text{cp}} = \frac{I_g + A \bar{h}^2}{A \bar{h}}
   \]
   where:
   - \(I_g\) is the second moment of area about the water surface, for a vertical rectangle, \(I_g = \frac{b h^3}{12}\).
   - \(A \bar{h}^2\) is a correction term for the centroid.

   Let me calculate both values.The calculations yield the following results:

1. **Total resultant hydrostatic force** on side ABCD:  
   \( F = 147.15 \, \text{kN} \)

2. **Location of the center of pressure** from the bottom of the tank:  
   \( h_{\text{cp}} = 1.11 \, \text{m} \)

These values don't exactly match any of the given options, which suggests a slight variation in interpretation or precision in the choices provided.

Would you like more details on the calculations, or should we explore further adjustments? Here are some related questions for practice:

1. How does increasing the depth of water affect the total resultant force?
2. How would the results change if the tank were filled with a different liquid (e.g., oil)?
3. How can the formula for center of pressure be applied to other shapes (e.g., trapezoids)?
4. How is the hydrostatic force distributed across the surface of the tank?
5. What would the force be if the tank were tilted?

**Tip**: When dealing with hydrostatic pressure, remember that pressure increases linearly with depth.

A tank containing water is shown. Calculate the total resultant force acting on the side ABCD of the container and the location of the center of pressure from the bottom.

Learn how to calculate the total resultant hydrostatic force acting on the side of a water tank and find the center of pressure using formulas for pressure, force, and second moment of area. This problem is ideal for university-level physics or engineering courses.

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