Math Problem Statement

Ravi and Priya received their scores in three mock exams. In the first exam, Ravi scored 8 more marks than Priya. In the second exam, Ravi scored 6 more marks than Priya. If Priya’s average score in the three exams was 5 marks higher than Ravi’s average score in the three exams, then Priya’s score in the third exam was how much more than Ravi’s score?

Solution

Let's break down the problem step by step.

We are given the following information:

  • First Exam:

    • Ravi scored 8 more marks than Priya.
    • Let Priya's score be p1p_1, so Ravi's score is p1+8p_1 + 8.
  • Second Exam:

    • Ravi scored 6 more marks than Priya.
    • Let Priya's score be p2p_2, so Ravi's score is p2+6p_2 + 6.
  • Third Exam:

    • Let Priya's score be p3p_3, and Ravi's score be r3r_3.
  • We are also told that Priya's average score over the three exams is 5 marks higher than Ravi's average score.

Thus, the relationships we have are:

  1. Ravi's total score: (p1+8)+(p2+6)+r3(p_1 + 8) + (p_2 + 6) + r_3
  2. Priya's total score: p1+p2+p3p_1 + p_2 + p_3

Their respective averages:

Ravi’s average=(p1+8)+(p2+6)+r33\text{Ravi's average} = \frac{(p_1 + 8) + (p_2 + 6) + r_3}{3} Priya’s average=p1+p2+p33\text{Priya's average} = \frac{p_1 + p_2 + p_3}{3}

According to the problem, Priya's average score is 5 more than Ravi's average score:

p1+p2+p33=(p1+8)+(p2+6)+r33+5\frac{p_1 + p_2 + p_3}{3} = \frac{(p_1 + 8) + (p_2 + 6) + r_3}{3} + 5

Multiplying both sides by 3 to eliminate the fractions:

p1+p2+p3=(p1+8)+(p2+6)+r3+15p_1 + p_2 + p_3 = (p_1 + 8) + (p_2 + 6) + r_3 + 15

Simplifying the equation:

p1+p2+p3=p1+p2+r3+29p_1 + p_2 + p_3 = p_1 + p_2 + r_3 + 29

Canceling p1p_1 and p2p_2 on both sides:

p3=r3+29p_3 = r_3 + 29

Thus, Priya's score in the third exam is 29 marks more than Ravi's score in the third exam.

Let me know if you'd like any additional details or clarifications! Here are some related questions:

  1. How would the result change if the difference in their average scores was different?
  2. How can you verify the solution by substituting hypothetical values for p1p_1, p2p_2, and p3p_3?
  3. What if the difference in scores was the same across all exams?
  4. Can this type of problem be modeled using matrices for multiple students?
  5. How would this problem change if one exam was weighted more than the others?

Tip: Always remember to clearly define your variables and set up equations carefully when solving word problems like this one.

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Math Problem Analysis

Mathematical Concepts

Algebra
Averages
Linear Equations

Formulas

Ravi's average = [(p1 + 8) + (p2 + 6) + r3] / 3
Priya's average = (p1 + p2 + p3) / 3
Priya's average = Ravi's average + 5

Theorems

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Suitable Grade Level

Grades 8-10