How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?

To calculate the power required to lift a 30.0 N weight 10.0 meters high in 5.00 seconds, we can use the formula:

\[
\text{Power} = \frac{\text{Work}}{\text{Time}}
\]

First, we calculate the work done:

\[
\text{Work} = \text{Force} \times \text{Distance} = 30.0 \, \text{N} \times 10.0 \, \text{m} = 300.0 \, \text{Joules}
\]

Next, we calculate the power:

\[
\text{Power} = \frac{300.0 \, \text{Joules}}{5.00 \, \text{seconds}} = 60.0 \, \text{Watts}
\]

So, it takes **60.0 Watts** of power to lift the 30.0 N weight 10.0 meters high in 5.00 seconds.

Would you like more details or have any questions?  

Here are five related questions to explore:
1. How would the power change if the time were reduced to 2.50 seconds?
2. What would happen to the power if the weight were doubled to 60.0 N?
3. How is power affected if the height is increased to 20.0 meters?
4. What is the relationship between power, force, and velocity in this context?
5. How much energy is required to lift the weight 10.0 m vertically, ignoring time?

**Tip:** Remember, power is a measure of how quickly work is done, so reducing the time or increasing the work will increase the power required.

Discover how to calculate the power needed to lift a 30.0 N weight 10.0 meters high in 5.00 seconds. This physics problem explores the concepts of work, energy, and power using formulas like Power = Work / Time. Perfect for students in Grades 9-11.

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