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The question in the image asks to calculate the potential energy ("tenaga keupayaan") of the Helios Prototype (HP01), a solar-powered unmanned aircraft that reached an altitude of 29,500 meters. The formula given for potential energy is \( E = mgh \), where:

- \( E \) is the potential energy,
- \( m \) is the mass of the aircraft (600 kg),
- \( g \) is the acceleration due to gravity (10 m/s\(^2\)),
- \( h \) is the altitude (29,500 m).

We can now use this information to calculate the energy:

\[
E = mgh = 600 \, \text{kg} \times 10 \, \text{m/s}^2 \times 29,500 \, \text{m}
\]

Let me compute that for you.The potential energy of the Helios Prototype (HP01) at an altitude of 29,500 meters is 177,000,000 joules (or 177 MJ).

Would you like any additional details or have questions about this?

Here are some related questions:
1. What other factors could affect the energy calculations for flying aircraft?
2. How does gravitational potential energy change with altitude?
3. How would the energy change if the altitude were doubled?
4. Can potential energy be converted into other forms of energy during flight?
5. How do different planets with varying gravity affect potential energy?

**Tip:** In many physics problems, air resistance is often ignored, but in reality, it can significantly impact energy calculations for objects moving through the atmosphere.

Kira tenaga keupayaan graviti pesawat Helios Prototype (HP01) pada ketinggian 29,500m menggunakan rumus, Tenaga Keupayaan = mgh, (g = 10ms^−2).

Learn how to calculate the gravitational potential energy of the Helios Prototype (HP01) at an altitude of 29,500 meters. Using the formula E = mgh, we find the energy for a 600 kg solar-powered aircraft. Suitable for Grades 9-12 physics students.

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