To calculate the population for the next year using the given arithmetic progression formula, we can follow these steps:

Given:

• Initial population in 2006 (P1) = 169,570
• Growth rate (GR) = 2.3% = 0.023 (in decimal form)
• Formula: $\text{New Population} = \text{GR} \times P1 + P1$

Calculation:

$\text{New Population} = 0.023 \times 169570 + 169570$

1. Calculate the increase in population: $0.023 \times 169570 = 3890.11$

2. Add the increase to the initial population: $3890.11 + 169570 = 173460.11$

So, the new population after one year, using this arithmetic progression, would be 173,460.11.

Would you like to go into more details or have any questions?

Related Questions:

1. What would the population be in 2008 using the same formula?
2. How would the population change if the growth rate was 3% instead of 2.3%?
3. Can you derive a general formula to calculate the population after $n$ years?
4. What is the total population increase from 2006 to 2034 using this method?
5. How does this arithmetic progression differ from a geometric progression in population growth?

Tip:

Arithmetic progression assumes a constant rate of change, which may not accurately reflect exponential growth patterns often seen in populations over long periods.