2006, 169570 population,2.3% annual population change. Using The arithmetic project 2006-2034. Where p1=169570, GR=0.023, use this formula GR×p1+p1 that is 0.023×169570+169570

To calculate the population for the next year using the given arithmetic progression formula, we can follow these steps:

### Given:
- **Initial population in 2006 (P1)** = 169,570
- **Growth rate (GR)** = 2.3% = 0.023 (in decimal form)
- **Formula**: \( \text{New Population} = \text{GR} \times P1 + P1 \)

### Calculation:
\[
\text{New Population} = 0.023 \times 169570 + 169570
\]

1. **Calculate the increase in population**:
   \[
   0.023 \times 169570 = 3890.11
   \]

2. **Add the increase to the initial population**:
   \[
   3890.11 + 169570 = 173460.11
   \]

So, the new population after one year, using this arithmetic progression, would be **173,460.11**.

Would you like to go into more details or have any questions?

### Related Questions:
1. What would the population be in 2008 using the same formula?
2. How would the population change if the growth rate was 3% instead of 2.3%?
3. Can you derive a general formula to calculate the population after \( n \) years?
4. What is the total population increase from 2006 to 2034 using this method?
5. How does this arithmetic progression differ from a geometric progression in population growth?

### Tip:
Arithmetic progression assumes a constant rate of change, which may not accurately reflect exponential growth patterns often seen in populations over long periods.

Learn how to calculate population growth using the arithmetic progression formula. Given an initial population of 169,570 in 2006 and an annual growth rate of 2.3%, discover the step-by-step process to determine the population for subsequent years up to 2034. Suitable for advanced high school students and those interested in mathematical modeling of population dynamics.

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