To find the percentage of all values in a normal distribution for the given z-score (where $z \geq 1.41$), we can follow a similar approach as before.

Step 1: Find the cumulative probability for $z = 1.41$

Using the standard normal distribution table or a calculator, we find the cumulative probability (area to the left) for $z = 1.41$.

The cumulative probability $P(Z < 1.41)$ is approximately 0.9207.

Step 2: Calculate the area to the right

Since we want the area to the right of $z = 1.41$, we subtract the cumulative probability from 1:

$P(Z \geq 1.41) = 1 - P(Z < 1.41) = 1 - 0.9207 = 0.0793$

Step 3: Convert to a percentage

To convert this to a percentage, multiply by 100:

$P(Z \geq 1.41) = 0.0793 \times 100 = 7.93\%$

Final Answer:

Approximately 7.93% of the values in a normal distribution have a z-score greater than or equal to 1.41.

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Would you like more details on the standard normal distribution, or do you have any other questions?

Here are 5 related questions you might find interesting:

1. What is the percentage for a z-score less than or equal to 1.41?
2. How do you calculate the percentage for $z \geq 1.96$?
3. Can you find the percentage for a z-score between 1.41 and 2.00?
4. How do you interpret z-scores in terms of standard deviations from the mean?
5. What is the significance of the 50th percentile in a normal distribution?

Tip: When using z-tables or calculators, remember that they typically provide the cumulative probability up to the given z-score (area to the left). To find the area to the right, simply subtract this value from 1.