To solve the expression \((\frac{20 \, \text{g}}{20 \, \text{g} + 10 \, \text{g}}) \times 100\%\), follow these steps:

1. **Add the weights in the denominator**:
   \[
   20 \, \text{g} + 10 \, \text{g} = 30 \, \text{g}
   \]

2. **Divide the weight in the numerator by the sum in the denominator**:
   \[
   \frac{20 \, \text{g}}{30 \, \text{g}} = \frac{20}{30}
   \]

3. **Simplify the fraction**:
   \[
   \frac{20}{30} = \frac{2}{3}
   \]

4. **Convert the fraction to a percentage by multiplying by 100**:
   \[
   \left(\frac{2}{3}\right) \times 100\% \approx 66.67\%
   \]

So, \((\frac{20 \, \text{g}}{20 \, \text{g} + 10 \, \text{g}}) \times 100\% \approx 66.67\%\).

Would you like further details or have any questions?

Here are some related questions you might explore:
1. What is the percentage if the weights are 30 g and 15 g?
2. How does the percentage change if the numerator weight is halved?
3. What if the denominator is doubled while keeping the numerator constant?
4. How to express the fraction \(\frac{2}{3}\) as a decimal?
5. How to convert a percentage back into a fraction?
6. What are some real-life applications of percentage calculations?
7. What would the result be if the weights were in milligrams instead of grams?
8. How to solve a similar problem if the numerator and denominator are in different units?

**Tip:** Always ensure to use the same units when calculating ratios or percentages to avoid errors.

Learn how to calculate the percentage from weights of 20 grams and 10 grams using a step-by-step solution. This problem covers key concepts including percentage calculation, ratios, and fractions. Suitable for students in Grades 6-8.

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