Math Problem Statement

A timekeeper measures the time it takes an athlete to complete a race to be 32.08 seconds. Calculate the percentage error of this measurement, correct to 4 decimal places.

Solution

To calculate the percentage error, we use the formula:

Percentage Error=(Absolute ErrorTrue Value)×100\text{Percentage Error} = \left( \frac{\text{Absolute Error}}{\text{True Value}} \right) \times 100

The absolute error is typically half of the smallest unit of measurement used by the timekeeper. Since the time is given as 32.08 seconds, the smallest unit of measurement is 0.01 seconds (since it is recorded to two decimal places).

Absolute Error=0.012=0.005 seconds\text{Absolute Error} = \frac{0.01}{2} = 0.005 \text{ seconds}

Now, applying the formula:

Percentage Error=(0.00532.08)×100\text{Percentage Error} = \left( \frac{0.005}{32.08} \right) \times 100

Let's compute this:

0.00532.08=0.0001559\frac{0.005}{32.08} = 0.0001559

0.0001559×100=0.0156%0.0001559 \times 100 = 0.0156\%

Thus, the percentage error is 0.0156%, correct to 4 decimal places.


Would you like a breakdown of the steps or more examples?

Related Questions:

  1. How does the number of decimal places affect the accuracy of measurements?
  2. What are some common sources of error in timekeeping for races?
  3. How can timekeeping be improved to minimize percentage errors?
  4. What is the difference between absolute error and relative error?
  5. How would the percentage error change if the race time was recorded as 32.1 seconds instead of 32.08?

Tip:

Always consider the precision of the measuring instrument when calculating errors—smaller divisions lead to more precise measurements!

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Math Problem Analysis

Mathematical Concepts

Error Analysis
Percentage Error
Absolute Error

Formulas

Percentage Error = (Absolute Error / True Value) × 100
Absolute Error = Smallest Unit of Measurement / 2

Theorems

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Suitable Grade Level

Grades 9-12