https://file.aiquickdraw.com/mathbot/file/1728171594294n17x9jgz.jpg

The question shown in the image asks:

"What is the percent error for the amount of snowfall? Round the percent to the nearest tenth if necessary."

The given information is:
- Predicted snowfall: 6.75 inches
- Actual snowfall: 10.25 inches

### Step-by-Step Solution

**Formula for Percent Error**:
\[
\text{Percent Error} = \left( \frac{|\text{Actual} - \text{Predicted}|}{\text{Actual}} \right) \times 100
\]

### Plugging in the values:
- Actual = 10.25 inches
- Predicted = 6.75 inches

1. Find the absolute difference between actual and predicted values:
\[
|\text{Actual} - \text{Predicted}| = |10.25 - 6.75| = 3.5
\]

2. Divide the absolute error by the actual value:
\[
\frac{3.5}{10.25} \approx 0.3415
\]

3. Multiply by 100 to convert to a percentage:
\[
0.3415 \times 100 = 34.15\%
\]

4. Round to the nearest tenth:
\[
\text{Percent Error} \approx 34.2\%
\]

### Final Answer:
The percent error for the amount of snowfall is approximately **34.2%**.

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Would you like a detailed explanation on how percent error works or have any other questions?

Here are some related questions to consider:
1. What does a large percent error indicate in real-life measurements?
2. How is percent error different from percent change?
3. Can percent error be negative? Why or why not?
4. How would the percent error change if the predicted and actual values were closer?
5. Why is it important to round to the nearest tenth?

**Tip**: Percent error is a useful way to quantify the accuracy of a prediction compared to actual outcomes. It's especially helpful when working with scientific or real-world data.

What is the percent error for the amount of snowfall? Round the percent to the nearest tenth if necessary.

Learn how to calculate the percent error for snowfall predictions using the given actual and predicted values. The problem involves basic percent error calculation and is ideal for students in Grades 6-8.

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