In a sample of iron ore are 18% is iron.How much ore is needed to produce 3600kg of iron

To determine how much ore is needed to produce 3,600 kg of iron, given that the ore contains 18% iron, we can set up the problem as follows:

Let's denote the total mass of ore required as \( x \) kg.

Since 18% of the ore is iron, the amount of iron in \( x \) kg of ore is \( 0.18x \) kg. We want this amount to equal 3,600 kg:

\[
0.18x = 3600
\]

To find \( x \), solve for \( x \):

\[
x = \frac{3600}{0.18} = 20000 \text{ kg}
\]

So, **20,000 kg** of ore is needed to produce 3,600 kg of iron.

Would you like a detailed explanation of each step, or do you have any further questions?

Here are five related questions you might find interesting:
1. What if the ore contained 25% iron instead? How much ore would be needed for the same amount of iron?
2. If you had 10,000 kg of this ore, how much iron could you extract?
3. How would the required ore change if only 15% of it were iron?
4. What is the ratio of iron to non-iron material in the ore?
5. If you needed 5,000 kg of iron, how much ore would be required?

**Tip:** Always double-check percentage calculations by considering the decimal equivalent (e.g., 18% = 0.18).

Learn how to calculate the amount of iron ore required to produce 3,600 kg of iron. Given that the ore contains 18% iron, find out the total mass of ore needed using percentage calculations and proportional reasoning. Suitable for Grades 7-9.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation