To find the net force ($\Sigma F$) acting on the object in the image, we can use Newton's Second Law, which states that:

$\Sigma F = m \cdot a$

where:

• $m = 4 \, \text{kg}$
• $a = 0.75 \, \text{m/s}^2$ (in the upward direction)

Substituting the values:

$\Sigma F = 4 \, \text{kg} \times 0.75 \, \text{m/s}^2 = 3 \, \text{N}$

Since the acceleration is upward, the net force $\Sigma F$ is also directed upward.

Now, let's verify if this net force matches the forces shown in the image:

• The image shows two forces: 3 N upward and 8 N to the right.
• For the net force to be 3 N upward, there would need to be no additional forces acting vertically other than the 3 N shown.

Therefore, the net force $\Sigma F$ acting on the object is indeed 3 N upward.

Would you like a further breakdown, or do you have additional questions?

Here are five related questions to deepen your understanding:

1. What would happen to the net force if the mass increased while the acceleration remained the same?
2. How would the net force direction change if there was an additional force acting downwards?
3. What is the resultant force if we consider both horizontal and vertical components?
4. How would you calculate the angle of the resultant force if there were multiple forces acting diagonally?
5. How would friction impact the forces and net force calculations in a real-world scenario?

Tip: Always consider both the magnitude and direction of forces when calculating net force in two-dimensional problems.