Math Problem Statement

To estimate the height of a mountain above a level plain, the angle of elevation to the top of the mountain is measured to be 32°. One thousand feet closer to the mountain along the plain, it is found that the angle of elevation is 34°. Estimate the height of the mountain. (Round your answer to the nearest foot.) ft

Solution

To estimate the height of the mountain, we can use trigonometric principles. Let's define the problem mathematically:

Setup:

  1. Let the height of the mountain be hh.
  2. Let the distance from the initial point of observation to the base of the mountain be dd.
  3. At the initial point, the angle of elevation is 3232^\circ, and 1000 feet closer to the mountain, the angle of elevation is 3434^\circ.

Using the tangent function: tan(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}

From the two observations, we can write: tan(32)=hdandtan(34)=hd1000\tan(32^\circ) = \frac{h}{d} \quad \text{and} \quad \tan(34^\circ) = \frac{h}{d - 1000}

Step 1: Express dd in terms of hh from the first equation:

d=htan(32)d = \frac{h}{\tan(32^\circ)}

Step 2: Substitute dd into the second equation:

tan(34)=hhtan(32)1000\tan(34^\circ) = \frac{h}{\frac{h}{\tan(32^\circ)} - 1000}

Simplify: tan(34)=hhtan(32)1000tan(32)tan(32)\tan(34^\circ) = \frac{h}{\frac{h \tan(32^\circ) - 1000 \tan(32^\circ)}{\tan(32^\circ)}}

Multiply through by tan(32)\tan(32^\circ): tan(34)(htan(32)1000tan(32))=htan(32)\tan(34^\circ) \cdot (h \tan(32^\circ) - 1000 \tan(32^\circ)) = h \tan(32^\circ)

Distribute: htan(34)tan(32)1000tan(34)tan(32)=htan(32)h \tan(34^\circ) \tan(32^\circ) - 1000 \tan(34^\circ) \tan(32^\circ) = h \tan(32^\circ)

Rearrange terms to isolate hh: h(tan(34)tan(32)tan(32))=1000tan(34)tan(32)h (\tan(34^\circ) \tan(32^\circ) - \tan(32^\circ)) = 1000 \tan(34^\circ) \tan(32^\circ)

Factor hh out: h=1000tan(34)tan(32)tan(34)tan(32)tan(32)h = \frac{1000 \tan(34^\circ) \tan(32^\circ)}{\tan(34^\circ) \tan(32^\circ) - \tan(32^\circ)}

Step 3: Calculate the height numerically:

Using tan(32)0.6249\tan(32^\circ) \approx 0.6249 and tan(34)0.6745\tan(34^\circ) \approx 0.6745: h=10000.67450.6249(0.67450.6249)0.6249h = \frac{1000 \cdot 0.6745 \cdot 0.6249}{(0.6745 \cdot 0.6249) - 0.6249}

h=10000.42140.42140.6249h = \frac{1000 \cdot 0.4214}{0.4214 - 0.6249}

h=421.40.04968497feet.h = \frac{421.4}{0.0496} \approx 8497 \, \text{feet.}

Final Answer:

The height of the mountain is approximately 8,497 feet.


Would you like me to provide step-by-step calculations for verification or further details?

Related Questions:

  1. How would the result change if the second angle of elevation were 35° instead of 34°?
  2. Can this method be applied if the ground is not level? How would it be adjusted?
  3. How do you derive the tangent function from a right triangle?
  4. What are other applications of trigonometric functions in real-life problems?
  5. How would rounding the tangent values to fewer decimals affect the result?

Tip:

When solving trigonometric problems, always double-check your angle mode (degrees vs. radians) in calculations to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Angle of Elevation
Tangent Function

Formulas

tan(θ) = opposite / adjacent
h = 1000 * tan(34°) * tan(32°) / [tan(34°) * tan(32°) - tan(32°)]

Theorems

Trigonometric Relationships in Right Triangles

Suitable Grade Level

Grades 10-12