Math Problem Statement
The price of a new car is $16,000. Assume that an individual makes a down payment of 25% toward the purchase of the car and secures financing for the balance at the rate of 8%/year compounded monthly. (Round your answers to the nearest cent.)
(a) What monthly payment will she be required to make if the car is financed over a period of 60 months?
Solution
To calculate the monthly payment for the car loan, we can use the formula for the monthly payment on an amortized loan. The formula is:
Where:
- = monthly payment
- = loan amount (after down payment)
- = monthly interest rate (annual rate divided by 12)
- = number of payments (loan term in months)
Step-by-Step Calculation:
-
Determine the down payment: The down payment is 25% of the car price:
-
Determine the loan amount: The loan amount is the car price minus the down payment:
-
Calculate the monthly interest rate: The annual interest rate is 8%, so the monthly rate is:
-
Number of payments: The loan is financed for 60 months, so .
-
Substitute into the formula:
Let's calculate this step-by-step:
Final Answer:
The monthly payment will be $243.73.
Would you like to see the details of the calculation process or have any further questions? Here's a list of related topics you might find interesting:
- How do you calculate the total amount paid over the life of the loan?
- What effect does changing the interest rate have on the monthly payment?
- How would the monthly payment change if the loan term were 72 months instead of 60?
- What is the difference between simple interest and compound interest in car loans?
- How would making extra payments impact the total cost of the car loan?
Tip: When comparing loan offers, always check the total interest paid over the life of the loan, as a lower monthly payment may not always mean the best deal.
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Math Problem Analysis
Mathematical Concepts
Loan Amortization
Compound Interest
Algebra
Formulas
M = P * r * (1 + r)^n / ((1 + r)^n - 1)
Theorems
Amortization formula
Compound interest formula
Suitable Grade Level
Grades 10-12
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