Solve this 43.25 g 
LiC2H3O2 what is the mole of oxygen, what is the mass and what is the atoms. Step by step

To solve the problem, we need to calculate:

1. The number of moles of oxygen in 43.25 g of Lithium Acetate (LiC₂H₃O₂).
2. The mass of oxygen.
3. The number of atoms of oxygen.

Lithium Acetate has the chemical formula \( \text{LiC}_2\text{H}_3\text{O}_2 \). Let's go step by step:

### Step 1: Calculate the molar mass of Lithium Acetate (LiC₂H₃O₂)
First, we need to find the molar mass of Lithium Acetate by adding up the atomic masses of each element:

- **Li (Lithium)**: 1 atom, atomic mass = 6.94 g/mol
- **C (Carbon)**: 2 atoms, atomic mass = 12.01 g/mol
- **H (Hydrogen)**: 3 atoms, atomic mass = 1.008 g/mol
- **O (Oxygen)**: 2 atoms, atomic mass = 16.00 g/mol

Now sum these values:

\[
\text{Molar mass of LiC}_2\text{H}_3\text{O}_2 = 6.94 + 2(12.01) + 3(1.008) + 2(16.00)
\]

\[
\text{Molar mass} = 6.94 + 24.02 + 3.024 + 32.00 = 65.984 \, \text{g/mol}
\]

### Step 2: Calculate the moles of Lithium Acetate
To calculate the number of moles of Lithium Acetate, use the formula:

\[
\text{Moles of LiC}_2\text{H}_3\text{O}_2 = \frac{\text{Mass}}{\text{Molar mass}}
\]

Given mass = 43.25 g and molar mass = 65.984 g/mol:

\[
\text{Moles of LiC}_2\text{H}_3\text{O}_2 = \frac{43.25}{65.984} = 0.6555 \, \text{mol}
\]

### Step 3: Calculate the moles of Oxygen atoms
In each mole of Lithium Acetate \( \text{LiC}_2\text{H}_3\text{O}_2 \), there are 2 oxygen atoms. Therefore, the number of moles of oxygen is:

\[
\text{Moles of oxygen} = 0.6555 \, \text{mol of LiC}_2\text{H}_3\text{O}_2 \times 2 \, \text{O atoms} = 1.311 \, \text{mol of O}
\]

### Step 4: Calculate the mass of Oxygen
Now, calculate the mass of oxygen. The molar mass of oxygen (O) is 16.00 g/mol, so the mass of oxygen is:

\[
\text{Mass of oxygen} = \text{Moles of oxygen} \times \text{Molar mass of oxygen}
\]

\[
\text{Mass of oxygen} = 1.311 \, \text{mol} \times 16.00 \, \text{g/mol} = 20.98 \, \text{g}
\]

### Step 5: Calculate the number of Oxygen atoms
Finally, use Avogadro’s number (\(6.022 \times 10^{23}\) atoms/mol) to calculate the number of oxygen atoms:

\[
\text{Number of atoms of oxygen} = 1.311 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol}
\]

\[
\text{Number of atoms of oxygen} = 7.89 \times 10^{23} \, \text{atoms of oxygen}
\]

### Summary of Results:
- **Moles of oxygen** = 1.311 mol
- **Mass of oxygen** = 20.98 g
- **Number of oxygen atoms** = \(7.89 \times 10^{23}\) atoms

Would you like more details or further clarification on any step?

Here are 5 related questions:
1. How do you calculate the number of hydrogen atoms in Lithium Acetate?
2. How would you calculate the number of moles if the mass were 50 g instead of 43.25 g?
3. How does Avogadro's number relate to the number of molecules in a substance?
4. What is the mass of carbon atoms in Lithium Acetate?
5. How can you determine the percentage composition of each element in a compound?

**Tip:** Always use Avogadro’s number when converting moles to atoms or molecules for precise results!

Solve this 43.25 g LiC2H3O2 what is the mole of oxygen, what is the mass and what is the atoms. Step by step

Learn how to calculate the moles, mass, and number of atoms of oxygen in 43.25 g of Lithium Acetate (LiC₂H₃O₂) with a step-by-step guide. This solution includes molar mass calculation, stoichiometry, and using Avogadro’s number for precise results. Suitable for Grades 10-12 Chemistry students.

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