Math Problem Statement

Jack called his Internet provider on 6 occasions to report connection problems. On each occasion, he noted the length of time he had to wait before speaking to an advisor. The times in minutes were as follows: 13, 16, 10, 22, 5, 12. Calculate the mean and standard deviation of these times.

Solution

The question asks to calculate the mean and standard deviation for the given times (in minutes): 13, 16, 10, 22, 5, and 12. Let's proceed with these calculations.

  1. Mean is calculated as: Mean=Sum of all valuesNumber of values\text{Mean} = \frac{\text{Sum of all values}}{\text{Number of values}}

  2. Standard deviation is calculated as: σ=(xiμ)2N\sigma = \sqrt{\frac{\sum (x_i - \mu)^2}{N}} where xix_i are the individual values, μ\mu is the mean, and ( N \

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Math Problem Analysis

Mathematical Concepts

Statistics
Mean
Standard Deviation

Formulas

Mean = (Sum of all values) / (Number of values)
Standard Deviation σ = sqrt(Σ(xi - μ)² / N)

Theorems

Properties of Arithmetic Mean
Standard Deviation Formula

Suitable Grade Level

Grades 9-12