Math Problem Statement

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of

51.751.7

degrees.

Low Temperature

​(circle◦​F)

40minus−44

45minus−49

50minus−54

55minus−59

60minus−64   Frequency

22

44

1313

44

11

Question content area bottom

Part 1

The mean of the frequency distribution is

enter your response here

degrees.

​(Round to the nearest tenth as​ needed.)

Solution

To find the mean of the frequency distribution, we can use the following steps:

Steps:

  1. Determine the midpoints for each temperature range (class).
  2. Multiply the midpoint by the corresponding frequency for each class.
  3. Sum these products.
  4. Divide the sum by the total number of observations (i.e., sum of frequencies).

Data provided:

  • Temperature ranges (°F):
    40-44, 45-49, 50-54, 55-59, 60-64
  • Frequencies:
    22, 44, 13, 4, 1

Step 1: Calculate the midpoints of each temperature range.

The midpoint for each range is the average of the lower and upper bounds.

Midpoint=Lower Bound+Upper Bound2\text{Midpoint} = \frac{\text{Lower Bound} + \text{Upper Bound}}{2}

  • Midpoint for 40-44: 40+442=42\frac{40 + 44}{2} = 42
  • Midpoint for 45-49: 45+492=47\frac{45 + 49}{2} = 47
  • Midpoint for 50-54: 50+542=52\frac{50 + 54}{2} = 52
  • Midpoint for 55-59: 55+592=57\frac{55 + 59}{2} = 57
  • Midpoint for 60-64: 60+642=62\frac{60 + 64}{2} = 62

Step 2: Multiply each midpoint by its corresponding frequency.

Product=Midpoint×Frequency\text{Product} = \text{Midpoint} \times \text{Frequency}

  • 42×22=92442 \times 22 = 924
  • 47×44=206847 \times 44 = 2068
  • 52×13=67652 \times 13 = 676
  • 57×4=22857 \times 4 = 228
  • 62×1=6262 \times 1 = 62

Step 3: Sum these products.

924+2068+676+228+62=3958924 + 2068 + 676 + 228 + 62 = 3958

Step 4: Divide the sum by the total number of observations (sum of frequencies).

Total number of observations =22+44+13+4+1=84= 22 + 44 + 13 + 4 + 1 = 84

Mean=39588447.1\text{Mean} = \frac{3958}{84} \approx 47.1

Conclusion:

The mean of the frequency distribution is approximately 47.1°F.

Now, comparing this to the actual mean of 51.7°F, we see that the computed mean is slightly lower.

Would you like any further explanation or have questions?

Here are five related questions:

  1. How do you interpret the difference between the computed and actual mean?
  2. What is the effect of outliers on the mean in a frequency distribution?
  3. How would you compute the median of the frequency distribution?
  4. Can the computed mean be a better estimate than the actual mean?
  5. What would happen if you increased the frequency of the highest temperature range?

Tip: The midpoint method for calculating the mean is useful when data is grouped into classes or ranges.

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Math Problem Analysis

Mathematical Concepts

Statistics
Mean
Frequency Distribution

Formulas

Midpoint = (Lower Bound + Upper Bound) / 2
Mean = Sum of (Midpoint × Frequency) / Total Frequency

Theorems

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Suitable Grade Level

Grades 9-12